Let the width and height be x and x and by using Pythagoras' theorem:
x2+x2 = 162
2x2 = 256
divide both sides by 2:
x2 = 128 (which will be the area of one of its faces)
6*128 = 768 square units
If the length of a side of the square is S units then the diagonal is S*sqrt(2) units in length.
Since the length and breadth are not given, the length of the diagonal can be anything from the smallest fraction to the largest number of units.
~26.16 units.
length = 7.2 units and width = 5.4 units Solved by means of Pythagoras' theorem.
13 units. Use Pythagoras.
If the length of a side of the square is S units then the diagonal is S*sqrt(2) units in length.
11.3137085 units
About 11.31 units.
Given the length of the diagonal of the square ... call it 'D units'. The area of the square is (1/2 D2) (same units)2.
Use Pythagoras' therom: 32+32 = 18 The square root of 18 is 4.242640687 units which is the length of the diagonal.
Since the length and breadth are not given, the length of the diagonal can be anything from the smallest fraction to the largest number of units.
sqrt(12.5) units
~26.16 units.
length = 7.2 units and width = 5.4 units Solved by means of Pythagoras' theorem.
d=x√2 where d is a diagonal and x is a side d=80√2 (or 113.137)
Using Pythagoras' theorem the length of the diagonal is 15 units
13 units. Use Pythagoras.