It is: 0.5*(n2-3n) = diagonals.
n side polygon has n(n-3)/2 diagonals therefore a hexagon has 9 diagonals
Total diagonals formula: 0.5*(n^2 -3n) whereas n is the number of sides of the polygon
An n-gon has n(n-3)/2 total diagonals. You can draw n-3 diagonals from each vertex ( n>3) ( A triangle doesn't really have a diagonal) An alternative way of seeing this: from any vertex, you can draw a diagonal to any other vertex except itself and the immediate neighbour on either side (the latter would be sides of the n-gon). This gives n-3 diagonals.
A normal convex polygon cannot have 15 diagonals. If it has n sides, it has n*(n-3)/2 diagonals and this is equal to 15 if n = 7.18. However, it is not possible for a polygon to have a fractional side.
1oo diagonals, because 1 side has 10 diagonals so 10 sides (10x10) = 100 diagonals! This is the correct answer..... a decagon has 35 diagonals. The equation for the this is D=n(n-3)/2 meaning diagonals = number of sides (N) multiplied by number of sides minus 3. and that number over 2. D=10(10-3)/2
Well, honey, a hexagonal prism has six sides, so it has six diagonals on the top face and six on the bottom face, making a total of 12 diagonals there. Then you've got the diagonals connecting the corresponding vertices on the top and bottom faces, which adds another 12 diagonals. So, in total, a hexagonal prism has 24 diagonals. Hope that clears things up for you, darling!
The formula is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
A nonagonal prism has two nonagonal bases and rectangular lateral faces. To find the total number of diagonals in a nonagonal prism, we first calculate the diagonals in one nonagon, which is given by the formula ( \frac{n(n-3)}{2} ). For a nonagon ((n = 9)), this results in 27 diagonals. Since the prism has two bases, the total number of diagonals in the prism is ( 27 + 27 + 18 = 72 ), where the 18 comes from the diagonals connecting vertices from one base to the other.
A polygon with n sides has 1/2*n*(n - 3) diagonals. So, for a polygon, with n = 12, there are 54 diagonals.
In a polygon with n sides there are n*(n-3)/2 diagonals. For a hexagon, n = 6 giving 9 diagonals in all.
An octacontakaidigon is a polygon with 82 sides. The formula to calculate the number of diagonals in a polygon is ( \frac{n(n-3)}{2} ), where ( n ) is the number of sides. For an octacontakaidigon, this would be ( \frac{82(82-3)}{2} = \frac{82 \times 79}{2} = 3239 ). Thus, an octacontakaidigon has a total of 3,239 diagonals.
An n sided polygon has n*(n-3)/2 diagonals.