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What is the formula for the number of diagonals in a hexagon?
n side polygon has n(n-3)/2 diagonals therefore a hexagon has 9 diagonals
What is the total number of diagonals?
Total diagonals formula: 0.5*(n^2 -3n) whereas n is the number of sides of the polygon
How many diagonals can be drawn from a vertex of an n-gon?
An n-gon has n(n-3)/2 total diagonals. You can draw n-3 diagonals from each vertex ( n>3) ( A triangle doesn't really have a diagonal) An alternative way of seeing this: from any vertex, you can draw a diagonal to any other vertex except itself and the immediate neighbour on either side (the latter would be sides of the n-gon). This gives n-3 diagonals.
Is a polygon with 8 sides have 15 diagonals?
A normal convex polygon cannot have 15 diagonals. If it has n sides, it has n*(n-3)/2 diagonals and this is equal to 15 if n = 7.18. However, it is not possible for a polygon to have a fractional side.
How many diagonals does a decagon have?
1oo diagonals, because 1 side has 10 diagonals so 10 sides (10x10) = 100 diagonals! This is the correct answer..... a decagon has 35 diagonals. The equation for the this is D=n(n-3)/2 meaning diagonals = number of sides (N) multiplied by number of sides minus 3. and that number over 2. D=10(10-3)/2
What are the total number of diagonals in a hexagonal prism?
A hexagonal prism has two hexagonal faces and six rectangular faces. To find the total number of diagonals in a hexagonal prism, we need to consider the diagonals within each face and the diagonals connecting vertices of different faces. Each hexagonal face has 9 diagonals, and each rectangular face has 2 diagonals. Therefore, the total number of diagonals in a hexagonal prism is calculated as (9 diagonals * 2 hexagonal faces) + (2 diagonals * 6 rectangular faces) = 18 + 12 = 30 diagonals.
How do you get the total number of diagonals of a polygon?
The formula is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
How many diagonals are there in a hexagon?
In a polygon with n sides there are n*(n-3)/2 diagonals. For a hexagon, n = 6 giving 9 diagonals in all.
How many diagonals to a dodecagon?
A polygon with n sides has 1/2*n*(n - 3) diagonals. So, for a polygon, with n = 12, there are 54 diagonals.
How many diagonals does a n-gon have of a polygon?
An n sided polygon has n*(n-3)/2 diagonals.
How many diagonals are in an octagon?
An Octagon has 20 diagonals in total. There is actually a really simple formula to figuring out the diagonals in any polygon: (n-3) x (n/2). If we put 8 in there than it would be (8-3) x (8/2) - 5x4=20, so the answer is 20 diagonals.
How many diagonals can be drawn from one vertex of a polygon of 50 sides?
47 sides. Take a vertex of an n-sided polygon. There are n-1 other vertices. It is already joined to its 2 neighbours, leaving n-3 other vertices not connected to it. Thus n-3 diagonals can be drawn in from each vertex. For n=50, n-3 = 50-3 = 47 diagonals can be drawn from each vertex. The total number of diagonals in an n-sided polygon would imply n-3 diagonals from each of the n vertices giving n(n-3). However, the diagonal from vertex A to C would be counted twice, once for vertex A and again for vertex C, thus there are half this number of diagonals, namely: number of diagonals in an n-sided polygon = n(n-3)/2.
