answersLogoWhite

0

What is the value of -2 times -2?

User Avatar

Anonymous

10y ago
Updated: 9/10/2022

The answer is 200 if you can't just multiply just on a piece of paper write down 100 + 100 and add it and you will get 200

User Avatar

Elmira Ebert

Lvl 9
2y ago

What else can I help you with?

Related Questions

What is the value of 2 times 2 times 5?

2*2*5 = 20


What is the value of 2 times 2 times 2 times 3 equal to?

2*2*2 = 8 8*3 = 24


What would be the answer to 2 times the absolute value of -5 minus 4 times the absolute value of 2 plus 3?

90


How do you find the answer for what is the value of 2 cubed?

To find the value of 2 cubed, you calculate (2^3), which means multiplying 2 by itself three times: (2 \times 2 \times 2). This results in (4 \times 2), which equals 8. Therefore, 2 cubed is 8.


How many times greater is the value of 2 in 270,413 than the value of the 2 in 419,427?

10,000 is grater than the 2 in 419,427


What is the value of 2 to the power of 3 times 3 to the power of 2?

48


How value of Root 2 is 1.414?

because 1.414... times itself = 2


What is the value of 2 to the power of 4 times 3?

48


What is the value of the product 4 divided by 3 times 3 divided by 2 times 2 divided by 1?

0.444444


How many times greater is the value of the 2 in 270413 than the value of the 2 in 416427?

The 2 in 270,413 is in the hundred thousand (100,000 = 10⁵) column The 2 in 416,427 is in the tens (10 = 10¹) column The 2 in 270,413 is 10⁵ ÷ 10¹ = 10⁴ = 10,000 times greater in value than the 2 in 416,427


What is the value of the expresion 3 xyplus 4 ycubed when x5 and y2?

3xy = 3 times 5 x 2 = 30 4y cubed = 4 times 2 x 2 x 2 =32 Total value 62


What numeric value in base 10 does the binary number 10000001 represent?

The binary number 10000001 represents the value of 129 in base 10. This is calculated by taking each digit of the binary number, multiplying it by 2 raised to the power of its position (from right to left, starting at 0). Specifically, (1 \times 2^7 + 0 \times 2^6 + 0 \times 2^5 + 0 \times 2^4 + 0 \times 2^3 + 0 \times 2^2 + 0 \times 2^1 + 1 \times 2^0 = 128 + 1 = 129).