0
(0, 0), of course. No linear term.
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∙ 11y ago
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Where is the vertex coordinate of the parabola y equals 24 -6x -3x squared when plotted on the Cartesian plane?
The vertex coordinate point of the vertex of the parabola y = 24-6x-3x^2 when plotted on the Cartesian plane is at (-1, 27) which can also be found by completing the square.
What is the vertex for y equals X raised to the second power?
The vertex is the origin, (0,0).
How do you write y equals x minus 4 x plus 2 in vertex form and find the vertex?
The given equation is y = x - 4x + 2 which can be written as y = -3x + 2 This is an equation of a straight line. Therefore it has no vertex and so cannot be written in vertex form.
X to the second power times -3x?
x2 * -3x = -3x3
What is the line of symmetry and the vertex when y equals 3x squared plus 2x minus 1?
y = 3x2+2x-1 Line of symmetry: x = -1/3 Vertex coordinate: (-1/3, -4/3)
What is the vertex of y equals 3x to the second power?
(0, 0) of course! No linear term! Review you vertex manipulation again.
Where is the vertex coordinate of the parabola y equals x square -3x -10 located on the Cartesian plane?
7
Where is the vertex coordinate of the parabola y equals 24 -6x -3x squared when plotted on the Cartesian plane?
The vertex coordinate point of the vertex of the parabola y = 24-6x-3x^2 when plotted on the Cartesian plane is at (-1, 27) which can also be found by completing the square.
What is the vertex for y equals X raised to the second power?
The vertex is the origin, (0,0).
How do you write y equals x minus 4 x plus 2 in vertex form and find the vertex?
The given equation is y = x - 4x + 2 which can be written as y = -3x + 2 This is an equation of a straight line. Therefore it has no vertex and so cannot be written in vertex form.
X to the second power times -3x?
x2 * -3x = -3x3
Find equation what parabola its vertex is 0 0 and it passes through point 2 12 express the equation in standard form?
Y=3x^2 and this is in standard form. The vertex form of a prabola is y= a(x-h)2+k The vertex is at (0,0) so we have y=a(x)^2 it goes throug (2,12) so 12=a(2^2)=4a and a=3. Now the parabola is y=3x^2. Check this: It has vertex at (0,0) and the point (2,12) is on the parabola since 12=3x2^2
What is the line of symmetry and the vertex when y equals 3x squared plus 2x minus 1?
y = 3x2+2x-1 Line of symmetry: x = -1/3 Vertex coordinate: (-1/3, -4/3)
A base angle of an isosceles triangle is 9 degrees more than the vertex angle Find the vertex angle?
let the vertex angle be x degrees, then the base angle is x + 9 degrees. Since in a triangle the sum of the angle is 180 degrees, and the base angles in an isosceles triangle are congruent, we have: x + 2(x + 9) = 180 x + 2x + 18 = 180 3x + 18 = 180 subtract 18 to both sides 3x = 162 divide by 3 to both sides x = 54 Thus the vertex angle is 54 degrees.
What is factored form of 3x to the 2nd power plus 6x?
x(3x+6) or 3x(x+2). Id recomend the second one.
What is the x coordinate of the vertex parabola defined by the following function 3x plus x plus 7x plus 4?
The given equation is not that of a parabola.
What are the coordinates of the vertex of the function below y minus 11 equals negative x minus 5 to the second power?
The vertex is (5, 11).
