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What is the slope and yintercept of y plus 4x plus 3?
There is no slope nor intercept because there is no equation, simply an expression.
How do you find the slope and y-intercept of an equation?
first of all, i dont see how slope and yintercept has anything to do with shopping. usually in an equation, y= mx+b, m stands for slope, and b is the y-intercept. x and y are just x and y. If the equation is mixed up, and is not in y=mx+b format, you need to solve to get y on one side, the slope, x, and whatever the presented constant is (which is the y-intercept) on the other side. hope this helps.
How do you verify the identity sinx cscx 1?
sinx cscx = 1 is the same thing as sinx(1/sinx) = 1 which is the same as sinx/sinx = 1. This evaluates to 1=1, which is true.
Parenthesis 1 plus tanx end parenthesis divided by sinx equals cscx plus secx?
(1 + tanx)/sinxMultiply by sinx/sinxsinx + tanxsinxDivide by sin2x (1/sin2x) = cscxcscx + tan(x)csc(x)tanx = sinx/cosx and cscx = 1/sinxcscx + (sinx/cosx)(1/sinx)sinx cancels outcscx + 1/cosx1/cosx = secxcscx + secx
Solve my homework problemIt's about using slope intercept form One problem is 2y equals 8x-2?
I shall do this one , but you must do the rest otherwise you will not learn. 2y = 8x - 2 is the given eq'n/ The straight line form is y = mx + c'. 'm' is the slope/gradient of the line 'c' is the y-intercept. So divide both sides by '2' ; this will result in 'y = ' Hence y = (8/2)x - 2/2 y = 4x - 1 is the straight line form of y = mx + c. So the slope is m = 4 The y-intercept is c = -1 NB for all linear equations this is the method. NNB Linear eq'n may appear in various forms. 2y = 8x - 2 2y - 8x = -2 2y - 8x + 2 = 0 y - 4x + 1 = 0 etc., So you need to algebraically rearrange into the y = mx + c form However, if there are powers of 'x' or 'y' it is NOT a straight line. Hope that helps!!!!
How do you rewrite y equals cscx to graph it?
You could try y = 1/sin(x) but I do not see how that helps.
What is a slope used for?
It shows the relationship of y in terms of x. [y = (yIntercept) + ((slope)*(x))] [slope = (y2 - y1)/(x2 - x1)]
What is the slope and yintercept of y plus 4x plus 3?
There is no slope nor intercept because there is no equation, simply an expression.
What is the integral of cscx?
- ln (cscx + cotx) + C You use u substitution.
How do you write an equation of a line that passes through the xintercep and yintercept?
You can write it either in standard form (ax + by = c) or in slope-intercept form (y = mx + b)
What is the derivative of 1 divided by sinx?
y=1/sinxy'=(sinx*d/dx(1)-1*d/dx(sinx))/(sin2x)y'=(sinx*0-1(cosx))/(sin2x)y'=(-cosx)/(sin2x)y'=-(cosx/sinx)*(1/sinx)y'=-cotx*cscx
How do you find the slope and y-intercept of an equation?
first of all, i dont see how slope and yintercept has anything to do with shopping. usually in an equation, y= mx+b, m stands for slope, and b is the y-intercept. x and y are just x and y. If the equation is mixed up, and is not in y=mx+b format, you need to solve to get y on one side, the slope, x, and whatever the presented constant is (which is the y-intercept) on the other side. hope this helps.
What is the equation in slope-intercept form of the line that has a slope of 5 and y-intercept of -3?
8
How do you verify the identity sinx cscx 1?
sinx cscx = 1 is the same thing as sinx(1/sinx) = 1 which is the same as sinx/sinx = 1. This evaluates to 1=1, which is true.
What is the derivative of cscx?
d/dx csc(x) = - csc(x) tan(x)
How do you find the derivative of - csc x - sin x?
d/dx (-cscx-sinx)=cscxcotx-cosx
What is the derivative of -cscxcotx?
Using the u substitution method of derivation (selecting sinx as u and cosxdx as du), you get f'(x)=cscx.
