answersLogoWhite

0


Best Answer

d/dx csc(x)

= - csc(x) tan(x)

User Avatar

Wiki User

13y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What is the derivative of cscx?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

How do you take the derivative of a trig function?

Trig functions have their own special derivatives that you will have to memorize. For instance: the derivative of sinx is cosx. The derivative of cosx is -sinx The derivative of tanx is sec2x The derivative of cscx is -cscxcotx The derivative of secx is secxtanx The derivative of cotx is -csc2x


How do you find the derivative of - csc x - sin x?

d/dx (-cscx-sinx)=cscxcotx-cosx


What is the anti-derivative of co secant x?

According to Wolfram Alpha, input:integral csc x it is -log[cot(x) + csc(x)] + constant You can verify this by taking the derivative of the purported integral.


What is the derivative of -cscxcotx?

Using the u substitution method of derivation (selecting sinx as u and cosxdx as du), you get f'(x)=cscx.


Can you use the equation given below to find the second derivative of pi divided by 6 if fx equals cscx?

pi divided by 6 is a constant and so its first derivative is 0. And since that is also a constant, the second derivative is 0. It is not clear what f(x) = csc(x) has to do with that!


What is the integral of cscx?

- ln (cscx + cotx) + C You use u substitution.


What is the anti derivative of the square root of 1-x2?

-1


How do you prove that the derivative of csc x is equals to -csc x cot x?

d/dx cscx = d/dx 1/sinx = d/dx (sinx)-1= -(sinx)-2 cosx = -cosx/sin2x = -1/sinx.cosx/sinx = -cscx cotx I suggest you copy this out onto paper so it is more clear. The / signs make it harder to see what is happening compared to horizontal divide lines.


What is the derivative of 1 divided by sinx?

y=1/sinxy'=(sinx*d/dx(1)-1*d/dx(sinx))/(sin2x)y'=(sinx*0-1(cosx))/(sin2x)y'=(-cosx)/(sin2x)y'=-(cosx/sinx)*(1/sinx)y'=-cotx*cscx


How do you verify the identity sinx cscx 1?

sinx cscx = 1 is the same thing as sinx(1/sinx) = 1 which is the same as sinx/sinx = 1. This evaluates to 1=1, which is true.


Is it derivative of or derivative from?

"Derivative of"


How do you rewrite y equals cscx to graph it?

You could try y = 1/sin(x) but I do not see how that helps.