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Q: What is the y coordinate on a line with equation y 4x 5 when x 8?
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What is the slope of a line perpendicular to the line with equation y 4x 5?

If you mean: y = 4x+5 then the perpendicular slope is -1/4


What is a line parallel to y equals -4x plus 5?

The equation of such a line is [ Y = -4x plus any number].


What is the equation of the line with slope of 7 and containing the point 8 and 5?

If the slope is 7 and the coordinate is (8, 5) then the straight line equation is y=7x-51


What is the equation of the line parallel to y equals 4x-5 that crosses the y-axis at plus 3?

It is: y = 4x+3


What points are on the line given by the equation y equals 5x?

Any point on the line is a solution to the equation, and any solution to the equation is a point on the line. Ie any point where the y coordinate is 5 times the x coordinate will be on the line; for example the points (0, 0), (1, 5), (2, 10), (-1, -5), (-2, -10) all lines on the line y = 5x.


Which point lies on the line described by the equation y plus 8 equals 4x - 5?

(5, -8)


In the slope- intersect equation of a line which part of the equation gives the y coordinate of the point where the line crosses the y axis?

As for example in the equation: y = 2x+5 the slope is 2 and the y intercept is 5


Which equation is best represented by a line containing the ponts 2 -5 and 4 3?

It is a straight line equation and its solution is worked out as follows:- Points: (2, -5) and (4, 3) Slope: (-5-3)/(2-4) = 4 Equation: y--5 = 4(x-2) => y = 4x-8-5 => y = 4x-13 Equation: y-3 = 4(x-4) => y = 4x-16+3 => y = 4x-13 So in slope-intercept form: y = 4x-13 whereas 4 is the slope and -13 is the y intercept


How do you find the vertex of the parabola associated with a quadratic equation?

You must first solve the equation for x, find the midpoint between the two x coordinates and substitute it into the equation to find the y coordinate I.E. If your equation was y=x^2+4x-5 1. Factorise the Equation and solve for x. x^2+4x-5 = (x+5)(x-1) So x+5=0 x = 0 - 5 x=-5 And x-1=0 x = 0 + 1 x = 1 So x = -5,1 Find the mid point/average: (-5+1)/2 = -2 So the x coordinate of the vertex is -2. Substitute this into the equation x^2+4x-5: (-2)^2 + 4*(-2) - 5 = 4 - 8 - 5 = -9 So the Coordinate of the vertex is (-2,-9). Hope this Helps, message me if you want more info.


What is the coordinate pair to y equals 2x plus 5?

There are infinitely many coordinate pairs - the coordinates of each point on the infinite line defined by the equation.


What is 3y equals 4x plus 15?

this is an equation of a line. it has a slope of 4/3 and a y-intercept of 5


What is the slope of every line perpendicular to the graph of this equation 4x plus 5y equals 7?

4x+5y = 7 5y = -4x+7 y = -4/5x+7/5 in slope intercept form So the slope of the perpendicular line is plus 5/4