0
Do you mean?
X^2 - 121 = 0
add 121 to each side
X^2 = 121
take square root of each side
x = (+/-) 11
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The equation for the circle below is x2 plus y2 equals 121 What is the length of the circles radius?
11 = sqrt of 121. it is a circle centred on the origin think what would happen on the line x=0 (The y axis) the equation simplifies to y2 = 121 or y =11 you can also think of eqn of a circle as x2+y2=r2
What is the discriminant in the quadratic equation x2 plus 11x plus 121 equals x plus 96?
The discriminant in the quadratic equation x2 + 11x + 121 = x + 96 is 0.Simplify the equation to the form Ax2 + Bx + C = 0 and you get x2 + 10x + 25 = 0. The discriminant is B2 - 4AC or 100 - (4)(1)(25) or 100 - 100 or 0.Not asked, but answered for completeness - since the discriminant is 0, there is one real solution, namely x = (-10 +/- 00.5) / 2 = -5
What is the standard form of x2 equals 3x-2?
x2 - 3x + 2 = 0
How do you answer the problem x2 plus 10x plus equals 0?
x2 + 10x = 0 x2 + 10x + 25 = 25 (x + 5)2 = 25 x + 5 = +-5 x1 = 0 x2 =10
What does x2-5x equals 0?
x2 - 5x = 0x (x - 5) = 0x = 0andx = 5
What number must you add to complete the square x2 plus 22x equals 0?
it is 121
What is the solution to the equation x2 plus 3 equals 124?
x2+3=124 x2=121 x= square root(121) x=11
What number is needed to complete the square x2 23x equals 0?
x2 23x equals 0
What is the discriminant in the quadratic equation x squared plus 11x plus 121 equals x plus 96?
x2+11x+121 = x+96 x2+11x-x+121-96 = 0 x2+10x+25 = 0 Discriminant = b2-4ac = 102-4*1*25 = 0 The discriminant is equal to 0 so the quadratic equation will have two equal roots. (x+5)(x+5) = 0 Therefore: x = -5 and also x = -5 the answer is 0
How do you solve x2 81 equals 0?
x: x2 - 81 = 0
X2 - 4 equals 0?
If: x2-4 = 0 Then: x = 2
X2 y2 equals 121 what is the radius?
If this is the equation of a circle, the answer is 11, except that there needs to be a plus sigb between the x2 and the y2
The equation for the circle below is x2 plus y2 equals 121 What is the length of the circles radius?
11 = sqrt of 121. it is a circle centred on the origin think what would happen on the line x=0 (The y axis) the equation simplifies to y2 = 121 or y =11 you can also think of eqn of a circle as x2+y2=r2
Solution set of x2 plus 49 equals 0?
x2 + 49 = 0 ∴ x2 = -49 ∴ x = 7i
What is x2 plus 7x equals - 2x2 plus 6 in the form ax2 bx c equals 0?
x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0
How do you solve 144x equals x2?
144X = X2 144X - X2 = 0 (144 - X)X = 0 X = 0 or X = 144
How many solutions to x2-10 equals 0?
x2-10 = 0 x2 = 10 x = the square root of 10
