I am going to assume that your question is telling us that this expression is equal to 0. If we do not know what it is equal to then we can not answer the question.
2x2 + 7x + 6 = 0
This factors easily to:
(x + 2) (2x + 3) = 0
Thus
x + 2 = 0
x = -2
and
2x + 3 = 0
x = -3/2
x = -1.5
2X2 + 3X - 4 = 0the discriminant is,b2 - 4ac32 - 4(2)(- 4)9 + 32 = 4141 > 1this means there are two real roots to this equation
y = 2x2 + 3 does not intersect the x-axis at all. It has two imaginary roots at ±i * square root of 3/2.
two complex
This is a quadratic equation question which will have two answers: 2x2+42 = x2+13x 2x2-x2-13x+42 = 0 x2-13x+42 = 0 Factorising the equation gives you: (x-6)(x-7) = 0 Therefore: x = 6 or x = 7
If the discriminant of a quadratic equal is zero then it will have two equal roots.
-2.5 + 1.6583123951777i-2.5 - 1.6583123951777i
2X2 + 3X - 4 = 0the discriminant is,b2 - 4ac32 - 4(2)(- 4)9 + 32 = 4141 > 1this means there are two real roots to this equation
There are none because the discriminant of the given quadratic expression is less than zero.
x = -2.5 + 1.6583123951777ix = -2.5 - 1.6583123951777iwhere i is the square root of negative one.
x=11+69/2 and x=11-69/2
x2 + 3x - 5 is an expression, not an equation. An equation may have roots, an expression does not. However, x2 + 3x - 5 = 0 is an equation and its roots are -4.1926 and 1.1926 (approx).
y = 2x2 + 3 does not intersect the x-axis at all. It has two imaginary roots at ±i * square root of 3/2.
two negative
two complex
2x2 - 5x - 3 = 0 A quadratic equation expressed in the form ax2 + bx + c = 0 has two real and distinct roots when b2 - 4ac is positive. Using the figures from the supplied equation then b2 - 4ac = 52 - (4 x 2 x -3) = 25 + 24 = 49. Therefore there are TWO real and distinct roots.
It has two complex roots.
If: 2x2 = 4 Then: x = the square root of 2