Yes, for example: | x | = 0 with the only solution: x = 0
Only a linear equation in one variable x , which is an equation of the form ax + b = 0, (where a is different than 0), has only one solution. The solution is: x = -b/a
Only if O x=3
If you have -2x = 0, to solve for x, divide each side by two. That results in x = -0/2, or x = 0. So there is only one solution.
Yes. x2-4x+4=0 (x-2)(x-2)=0 x=2
3
The only solution to this is x=0.
Yes, of course. In this sense, it is a number just like any number. In general, an equation can have zero, one, or several solutions; the solutions can be positive, negative, zero, fractional, irrational, or complex, depending on the equation. Here is an equation that has zero as its solution: x = 0 (this is only an equality if your replace "x" with 0). Here are less trivial examples: x + 1 = 1 (the only solution is x = 0) x2 - x = 0 (two solutions: 0, and 1)
x2+x-6=0 * * * * * Perhaps the solution you are looking for is: x2 + x - 6 = (x - 2)(x + 3) = 0; whence, x = 2 or -3.
when the variable is to the power one you will only have one answer....2 solutions when to the power 23 when cubed etc.note: when multiple answers it is possible for answers to repeat ex. x^2+4x+4 =0would factor to (x+2)(x+2)=0 so x=-2 and x=-2 there is only one answer but it repeats. [Note: the graph of this parabola will 'just touch' the x-axis at x = -2]Also, it may seem that there is only one solution, for example x³ - 5x² + 8x - 6 = 0 looks like it only has one solution at x = 3 (as the graph of it will only cross the x-axis once at x = 3), but there are two more solutions which require the use of complex numbers, in this case namely x = 1 + i, and x = 1 - i (where i = √-1).
when the variable is to the power one you will only have one answer....2 solutions when to the power 23 when cubed etc.note: when multiple answers it is possible for answers to repeat ex. x^2+4x+4 =0would factor to (x+2)(x+2)=0 so x=-2 and x=-2 there is only one answer but it repeats. [Note: the graph of this parabola will 'just touch' the x-axis at x = -2]Also, it may seem that there is only one solution, for example x³ - 5x² + 8x - 6 = 0 looks like it only has one solution at x = 3 (as the graph of it will only cross the x-axis once at x = 3), but there are two more solutions which require the use of complex numbers, in this case namely x = 1 + i, and x = 1 - i (where i = √-1).
The way we create a perfect square trinomial is by squaring something in the form of (x-a) where a is some real number. For example (x-2)2 is x2 -4x+4 which is a perfect square trinomial. Not, write this as (x-2)(x-2) instead of (x-2)2 . To find the solutions, we write (x-2)(x-2)=0 The only solution that will make the left side equal to zero is 2. So in general, if we have a perfect square trinomial with the unknown as x, think of it as (x-a)2 or as (x-a)(x-a), then if we set this to 0, the one and only solution is x=a