IMPOSSIBLE
x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)
The answer to x4+x3-14x2+4x+6 divided by x-3 is x3+4x2-2x-2
Dividend: 4x4-x3+17x2+11x+4 Divisor: 4x+3 Quotient: x3-x2+5x-1 Remainder: 7
x(x + 4)(x - 4) or x3 - 16x
x3 - 2x2 - 4x + 8 = (x2 - 4)(x - 2) = (x + 2)(x - 2)(x - 2)
(x + 2)(x^2+4)
[ x3 - 4x2 + 7x ] / (x) = x2 - 4x + 7
x3 + 6x2 - 4x - 24 = (x + 6)(x2 - 4) = (x + 6)(x + 2)(x - 2)
64 is the cube of 4 so: x3 + 64 = (x + 4)(x2 - 4x + 16)
If x = 3 and y = 4 then the answer is 2
Dividend: 4x^4 -x^2 +17x^2 +11x +4 Divisor: 4x +3 Quotient: x^3 -x^2 +5x -1 Remainder: 7