1001 is the lowest four-digit palindrome, which is 0 modulus 7. Adding one to the first and last digits adds 0 modulus 7. Adding one to the second and third digits adds 5 modulus 7, since 110 is also 5 modulus 7. So only 770 plus multiples of 1001 are divisible by 7. Out of 90 possibilities, there are only 9 that are divisible by 7. So the probability is 9/90, or 1/10.
P(7)= 1/30
6561
The probability is 0.The probability is 0.The probability is 0.The probability is 0.
The probability is 7/36
None of the digits can be 10, so the probability is 0.
It is possible to create a 3-digit number, without repeated digits so the probability is 1.
1001 is the lowest four-digit palindrome, which is 0 modulus 7. Adding one to the first and last digits adds 0 modulus 7. Adding one to the second and third digits adds 5 modulus 7, since 110 is also 5 modulus 7. So only 770 plus multiples of 1001 are divisible by 7. Out of 90 possibilities, there are only 9 that are divisible by 7. So the probability is 9/90, or 1/10.
you forgot the last 2 digits of your user ID for a games website. You know that both digits are odd. Find the probability that you type the correct last digits by randomly typing 2 odd numbers
7 digits
The probability is 2:7.
P(7)= 1/30
The question is ambiguous. It is in complete.
6561
The probability is 0.The probability is 0.The probability is 0.The probability is 0.
The probability is 7/36
It is used in whole world.7 digits.1K=103 1,000 -------->4 digits.1M=106 1,000,000. ------>7 digits.