It is 1. Think of any number between 1 and 10 million.
If the last two digits of your password can be any combination of digits from 00 to 99, there are a total of 100 possible combinations. If you randomly select two digits, the probability of choosing the correct combination is 1 out of 100. Therefore, the probability of randomly choosing the correct last two digits is 1/100, or 1%.
1001 is the lowest four-digit palindrome, which is 0 modulus 7. Adding one to the first and last digits adds 0 modulus 7. Adding one to the second and third digits adds 5 modulus 7, since 110 is also 5 modulus 7. So only 770 plus multiples of 1001 are divisible by 7. Out of 90 possibilities, there are only 9 that are divisible by 7. So the probability is 9/90, or 1/10.
P(7)= 1/30
6561
It is used in whole world.7 digits.1K=103 1,000 -------->4 digits.1M=106 1,000,000. ------>7 digits.
None of the digits can be 10, so the probability is 0.
If the last two digits of your password can be any combination of digits from 00 to 99, there are a total of 100 possible combinations. If you randomly select two digits, the probability of choosing the correct combination is 1 out of 100. Therefore, the probability of randomly choosing the correct last two digits is 1/100, or 1%.
It is possible to create a 3-digit number, without repeated digits so the probability is 1.
1001 is the lowest four-digit palindrome, which is 0 modulus 7. Adding one to the first and last digits adds 0 modulus 7. Adding one to the second and third digits adds 5 modulus 7, since 110 is also 5 modulus 7. So only 770 plus multiples of 1001 are divisible by 7. Out of 90 possibilities, there are only 9 that are divisible by 7. So the probability is 9/90, or 1/10.
you forgot the last 2 digits of your user ID for a games website. You know that both digits are odd. Find the probability that you type the correct last digits by randomly typing 2 odd numbers
7 digits
The probability is 2:7.
P(7)= 1/30
The question is ambiguous. It is in complete.
6561
It is used in whole world.7 digits.1K=103 1,000 -------->4 digits.1M=106 1,000,000. ------>7 digits.
The probability is 7/36