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Write an equation of the line that has a slope of 3 and contains the point 2 5 in point-slope form?
Point on line = (2,5), therefore, x = 2 and y = 5 Slope = 3 Slope-intercept = ? Slope-intercept form: y = mx + b, where m = slope and b = y-intercept. y = mx + b; Solve for b: 5 = 3(2) + b 5 = 6 + b -6 + 5 = 6 + b -6 -1 = b So the equation of the line is y = 3x -1
What is the point-slope form of an equation passing through the points -6-4 and 2-5?
Point-slope form: y - y1 = m(x - x1) y+6=-1/8(x+4)
A line that passes through the point -1 3 has a slope of 2. Find another point on the line a.-3 2 b.0 5 c.1 4?
so the equation of this line can be written using the slope and the point using point slope form (y-3)=2(x+1) So y =2x+5 Now we see, for the points (0,5) is on the line since 2(0)+5=5
Write the equation in slope intercept form of the line that has a slope of -3 and contains the point 4 -5?
y- -5 = -3(x-4) y = -3x+12-5 y = -3x+7 in slope intercept form
Write the equation in slope intercept form of the line that has a slope of -3 and contains the point 4 5?
y -5 = -3(x -4) y = -3x+12+5 y = -3x+17 in slope intercept form
What is the point-slope form of a line with a slope -5 that contains the point (2-1)?
Point: (2, -1) Slope: -5 Equation: y = -5x+9
Given point (-6 -2) and a slope of 5 what is the equation in slope form?
Point: (-6, -2) Slope: 5 Equation: y = 5x+28
How do write an equation of a line when given the slope a point of the line?
if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
The slope of a line is 2 and the point 5 8 is on the line Express the line in slope-intercept form?
y = 2x - 2
How do you write -10 3 and -2 -5 in point slope form?
Points: (-10, 3) and (-2, -5) Slope: -1 Equation: y = -x-7
Write the equation in slope intercept form of the line that has a slope of 3 and contains the point 2 5?
y=2x+1
How do you graph a line in slope intercept for?
1) You write the equation in slope-intercept form, if it isn't in that form already. 2) An easy way to graph it is to start with the y-intercept. For example, if the intercept is +5, you graph the point (0, 5). Then you add an additional point, according to the slope. For example, if the slope is 1/2, you go 2 units to the right, and one up, and graph a point there.
Write an equation of the line that has a slope of 3 and contains the point 2 5 in point-slope form?
Point on line = (2,5), therefore, x = 2 and y = 5 Slope = 3 Slope-intercept = ? Slope-intercept form: y = mx + b, where m = slope and b = y-intercept. y = mx + b; Solve for b: 5 = 3(2) + b 5 = 6 + b -6 + 5 = 6 + b -6 -1 = b So the equation of the line is y = 3x -1
Which equation in point-slope form passes through 3-1 and has a slope of 2?
It is: y-1 = 2(x-3) => y = 2x-5
Which point lies on the line with point-slope equation y - 2 5(x - 6)?
If you mean: y-2 = 5(x-6) then the point is (6, 2) and the slope is 5
Which point lies on the line with point slope equation y - 2 5(x-6)?
If you mean: y-2 = 5(x-6) then the point is (6, 2) and the slope is 5
What is the equation in slope-intercept form of the line that has a slope of -3 and contains the point (4 -5).?
Slope: -3 Point: (4, -5) Equation: y = -3x+7
