Point slope form of y-7=-3x identifies the line that pass through the slope of line (-2 -5) (7 -6).
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Point on line = (2,5), therefore, x = 2 and y = 5 Slope = 3 Slope-intercept = ? Slope-intercept form: y = mx + b, where m = slope and b = y-intercept. y = mx + b; Solve for b: 5 = 3(2) + b 5 = 6 + b -6 + 5 = 6 + b -6 -1 = b So the equation of the line is y = 3x -1
Point-slope form: y - y1 = m(x - x1) y+6=-1/8(x+4)
so the equation of this line can be written using the slope and the point using point slope form (y-3)=2(x+1) So y =2x+5 Now we see, for the points (0,5) is on the line since 2(0)+5=5
y- -5 = -3(x-4) y = -3x+12-5 y = -3x+7 in slope intercept form
y -5 = -3(x -4) y = -3x+12+5 y = -3x+17 in slope intercept form