If you mean: y-2 = 5(x-6) then the point is (6, 2) and the slope is 5
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if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
Every point equidistant from (4, 1) and (10, 1) lies on the line [ x = 7 ],and that's the equation.
upon itself
If you represent the original straight line on a graph using Cartesian co-ordinates, it's equation will be y=mx+c where y and x are the variables and m and c are constants. (m will equal the gradient of the line. c will be the point where the line cuts through the y axis). Your new line, parallel to the original will be y=mx +c +d where d is the vertical distance between the point and the original line.
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
A point lies on a line if the coordinates of the point satisfy the equation of the line.
Without an equality sign it can not be considered to be an equation
(6,2)
Without an equality sign the given terms can't be considered to be an equation of a straight line.
That of course would depend on the straight line equation that has not been given and so therefore an answer is not possible.
Substitute the x coordinate into the equation for x and calculate y. If the formla gives the same y value as the coordinates, the point is on the line. If it is diffent, it is not on the line.
Without an equality sign the given expression can't be considered to be an equation.
A number of point lies on it...................(-2,-44), (-1,-19),(0,6), (1,31), (2, 56)...............
79
(5, -8)
If it is a straight line, then the equation is linear.
Finding the point that lies on the line described by the equation y - 8 - 3x - 6 can be easily found. Plug in the appropriate (x,y) values, one at a time, and you will find the value for the variable you did not plug in/