If you mean: y-2 = 5(x-6) then the point is (6, 2) and the slope is 5
if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
Every point equidistant from (4, 1) and (10, 1) lies on the line [ x = 7 ],and that's the equation.
upon itself
If you represent the original straight line on a graph using Cartesian co-ordinates, it's equation will be y=mx+c where y and x are the variables and m and c are constants. (m will equal the gradient of the line. c will be the point where the line cuts through the y axis). Your new line, parallel to the original will be y=mx +c +d where d is the vertical distance between the point and the original line.
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
A point lies on a line if the coordinates of the point satisfy the equation of the line.
Without an equality sign it can not be considered to be an equation
(6,2)
Without an equality sign the given terms can't be considered to be an equation of a straight line.
That of course would depend on the straight line equation that has not been given and so therefore an answer is not possible.
To determine if a point is on a line, you can substitute the coordinates of the point into the equation of the line. If the equation holds true after substitution, the point lies on the line. For example, for a line defined by (y = mx + b), if you plug in the x-coordinate of the point and the resulting y-value matches the y-coordinate of the point, then it is on the line. Otherwise, the point is not on the line.
Substitute the x coordinate into the equation for x and calculate y. If the formla gives the same y value as the coordinates, the point is on the line. If it is diffent, it is not on the line.
Without an equality sign the given expression can't be considered to be an equation.
A number of point lies on it...................(-2,-44), (-1,-19),(0,6), (1,31), (2, 56)...............
To determine which point lies on the line described by the equation ( y + 4 = 4x - 3 ), we first simplify the equation to ( y = 4x - 7 ). Then, we can test specific points by substituting their coordinates into this equation to see if they satisfy it. For instance, if we test the point (2, 1), substituting ( x = 2 ) gives ( y = 4(2) - 7 = 1 ), confirming that (2, 1) lies on the line.
To determine if a point is on a line, you can use the equation of the line. For example, if the line is represented by the equation (y = mx + b) (slope-intercept form), substitute the x-coordinate of the point into the equation to see if the resulting y-value matches the point's y-coordinate. If they match, the point lies on the line; if not, it does not. Alternatively, you can use other forms of the line equation, such as standard form, to perform a similar check.
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