The factors of (x2 + 11x + 30) are (X + 5) and (x + 6)You want to look for two numbers, when multiplied equal 30, and when added equal 11. Start with factors of 30, and see what they add to: 5+6=11, and 5*6=30.
x2 + 11x + 30 = 0 (x + 5)(x + 6) = 0 so the roots are -5 and -6
572 Because 2x11=22 and 13x2=26 and 22x26=572.
The actual equation itself is the polynomial. There is no polynomial for it, and your question doesn't really make sense.
It is: x^2 +11x +24 = (x+8)(x+3) when factored
The factors of (x2 + 11x + 30) are (X + 5) and (x + 6)You want to look for two numbers, when multiplied equal 30, and when added equal 11. Start with factors of 30, and see what they add to: 5+6=11, and 5*6=30.
x2 + 11x + 30 = 0 (x + 5)(x + 6) = 0 so the roots are -5 and -6
572 Because 2x11=22 and 13x2=26 and 22x26=572.
x^3 - 121x
X2 -11x +10=(x - 1 )(x - 10)
x2 + 11x + 18 (x + 9)(x + 2) CHECK: x2 + 9x + 2x + 18 x2 + 11x + 18 SET EACH EQUAL TO ZERO: x + 9 = 0 x = -9 x + 2 = 0 x = -2 NOW YOU ARE DONE: Solution set: {-9, -2}
x^2 + 11x + 6 has no rational zeros.
x2+11x+11 = 7x+9 x2+11x-7x+11-9 = 0 x2+4x+2 = 0 The above quadratic equation can be solved by using the quadratic equation formula and it will have two solutions.
The actual equation itself is the polynomial. There is no polynomial for it, and your question doesn't really make sense.
It is: x^2 +11x +24 = (x+8)(x+3) when factored
X2+11x+11 = 7x+9 X2+11x-7x+11-9 = 0 x2+4x+2 = 0 Solve as a quadratic equation by using the quadratic equation formula or by completing the square: x = -2 + or - the square root of 2
Assuming the question is written as: x2+11x-12 This would factor to: (x+12)(x-1)