2x-3=10x+21
2x-3-2x=10x+21-2x
-3=8x+21
-3-21=8x+21-21
-24=8x
-3=x
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-3x + 10x - 5 + 26 = 7x + 21
They are parallel lines.
Assuming x(2-10x)=21 to be solved for x, distribute to -10x2+2x=21, or 10x2-2x+21=0. By the quadratic equation, we can determine there are no real solutions because the square root of -836 does not exist. In imaginary solutions, we can reduce to 1/10*(1 + sqrt(-209)) and 1/10*(1-sqrt(-209)) as solutions.
x = 3, y = 3
8/-3 + -7/2 = 8x-2/-3x-2 + -7x3/2x3= -16/6 + -21/6= -37/6