Q: 2x-3 equals 10x plus 21

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-3x + 10x - 5 + 26 = 7x + 21

They are parallel lines.

Assuming x(2-10x)=21 to be solved for x, distribute to -10x2+2x=21, or 10x2-2x+21=0. By the quadratic equation, we can determine there are no real solutions because the square root of -836 does not exist. In imaginary solutions, we can reduce to 1/10*(1 + sqrt(-209)) and 1/10*(1-sqrt(-209)) as solutions.

x = 3, y = 3

8/-3 + -7/2 = 8x-2/-3x-2 + -7x3/2x3= -16/6 + -21/6= -37/6

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x2 + 10x + 21 = (x + 3)(x + 7)

2x-3 = 21+10x 2x-10x = 21+3 -8x = 24 x = -3

-171 = 19x so x = -9

(x2+10x+21)/(x+3) = (x+7)

It is: x2-10x+21 = 0 and the value of x is 3 or 7 when solved

-3x + 10x - 5 + 26 = 7x + 21

x2+10x+21 = (x+3)(x+7)

10x+15 = 7x-21 10x-7x = -21-15 3x = -36 x = -12 Which is the solution to the above equation when simplified.

Factorising, we obtain, x2 + 10x + 21 = (x + 7)(x + 3). Thus, x2 + 10x + 21 / (x + 3) = x + 7. That's usually easier than dividing it out!

The roots are -3 and -7. Easily by factoring and setting each factor equal to 0. The factors are x + 7 and x +3.

x2 + 10x + 21 = (x + 3)(x + 7) You need to find 2 numbers which sum to 10 and whose product of 21. In this case 3 + 7 = 10 and 3 x 7 = 21.

(x-7)(x-3)