(x2+10x+21)/(x+3) = (x+7)
x2 + 10x + 21 = (x + 3)(x + 7)
2x-3 = 21+10x 2x-10x = 21+3 -8x = 24 x = -3
21
x2 + 10x + 21 = (x + 3)(x + 7) You need to find 2 numbers which sum to 10 and whose product of 21. In this case 3 + 7 = 10 and 3 x 7 = 21.
(x - 7)(x - 3)
(x2+10x+21)/(x+3) = (x+7)
x2 + 10x + 21 = (x + 3)(x + 7)
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2x-3 = 21+10x 2x-10x = 21+3 -8x = 24 x = -3
-3x + 10x - 5 + 26 = 7x + 21
x2+10x+21 = (x+3)(x+7)
2x-3=10x+21 2x-3-2x=10x+21-2x -3=8x+21 -3-21=8x+21-21 -24=8x -3=x
21
x2 + 10x + 21 = (x + 3)(x + 7) You need to find 2 numbers which sum to 10 and whose product of 21. In this case 3 + 7 = 10 and 3 x 7 = 21.
(x-7)(x-3)
21