Factorising, we obtain,
x2 + 10x + 21 = (x + 7)(x + 3).
Thus,
x2 + 10x + 21 / (x + 3) = x + 7.
That's usually easier than dividing it out!
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(x2+10x+21)/(x+3) = (x+7)
x2 + 10x + 21 = (x + 3)(x + 7)
2x-3 = 21+10x 2x-10x = 21+3 -8x = 24 x = -3
21
x2 + 10x + 21 = (x + 3)(x + 7) You need to find 2 numbers which sum to 10 and whose product of 21. In this case 3 + 7 = 10 and 3 x 7 = 21.