It is: (c-4)(c-8) when factored
This is the common form of the Pythagorean Theorem. It describes the relationship between the two legs of a right triangle and the hypotenuse.
Since a squared plus b squared equals c squared, that is the same as c equals the square root of a squared plus b squared. This can be taken into squaring and square roots to infinity and still equal c, as long as there is the same number of squaring and square roots in the problem. Since this question asks for a and b squared three times, and also three square roots of a and b both, they equal c. Basically, they cancel each other out.
c= sq rt of 73
A squared plus B squared equals C squared. It is the Pythagorean theorem.To do this you would find the two short sides of a right triangle. Then for one short side find the length and multiply it by itself and for the other short side do the same thing. After that add those two up and and find the square root of it. That number you have there is C aka hypotenuse aka the long side. :)
4
2. c2 + c2 + 8 = 8c 2c2 - 8c + 8 = 0 c2 - 4c + 4 = 0 (c - 2)(c - 2) = 0 (c - 2)2 = 0 c - 2 = 0 c = 2
It is: (c-4)(c-8) when factored
It is: 3x2+6x-11 = 0
Pythagoras developed the method to solve this- A squared plus B squared equals C squared. A squared= 8x8, added to B squared (also 8x8) So that is 64+64 or 128. So 128 is line C squared. Find the square root of 128, and you have C, which is the diagonal. (Hint- it is 11.31)
* a2 + b2 = c2 * a = 3 * b = 8 * (3)2 + (8)2 = c2 * 9 + 64 = c2 * 73 = c2 * c = √73
The Pythagoream Thereom is a^2 + b^2 = c^2. Written out it is a squared plus b squared equals c squared.
This is the common form of the Pythagorean Theorem. It describes the relationship between the two legs of a right triangle and the hypotenuse.
a squared plus b squared is c squared
pythagoras
40b squared c squared divide 5bc = 8
Since a squared plus b squared equals c squared, that is the same as c equals the square root of a squared plus b squared. This can be taken into squaring and square roots to infinity and still equal c, as long as there is the same number of squaring and square roots in the problem. Since this question asks for a and b squared three times, and also three square roots of a and b both, they equal c. Basically, they cancel each other out.