n + 1/4 = 9/20 n + 5/20 = 9/20 n = 4/20 = 1/5
n=9. Because n+42=51. Subtract 42 from both sides and n=9
To find the value of n -7n=63 n=63/-7 n-9 Hence,-9 is the required answer.
2n/6 - 9 or n/3 - 9
Let the two numbers be 'm' & 'n' Sum = m + n = -9 Product is mn = -90 Hence m = -90/n Substitute -90/n + n = -9 Multiply through by 'n' -90 + n^2 = - 9n n^2 + 9n - 90 = 0 It is now in quadratic form ; factor (n + 15)(n - 6) = 0 n = -15 & n = 6
echo "*** Converting between the different temperature scales ***" echo "1. Convert Celsius temperature into Fahrenheit" echo "2. Convert Fahrenheit temperatures into Celsius" echo -n "Select your choice (1-2) : " read choice if [ $choice -eq 1 ] then echo -n "Enter temperature (C) : " read tc # formula Tf=(9/5)*Tc+32 tf=$(echo "scale=2;((9/5) * $tc) + 32" |bc) echo "$tc C = $tf F" elif [ $choice -eq 2 ] then echo -n "Enter temperature (F) : " read tf # formula Tc=(5/9)*(Tf-32) tc=$(echo "scale=2;(5/9)*($tf-32)"|bc) echo "$tf = $tc" else echo "Please select 1 or 2 only" exit 1 fi
Tc = (5/9)*(Tf-32) {Equation for Celsius} Tf = (9/5)*Tc+32 {Equation for Fahrenheit}
Short is a relative term when you're talking about a 3100-mile trip, but from Halifax to Calgary, take 102 N to the Trans-Canada heading west and follow all its permutations from TC-104W through TC-2W, TC N, TC O, TC-W and TC-1W Start paying attention again when you hit Moose Jaw. Medicine Hat is the first town in Alberta.
It's easy to convert from Celsius to Fahrenheit by yourself. Tf = (9/5)*Tc+32, where Tc = temperature in degrees Celsius, Tf = temperature in degrees Fahrenheit. -9 C is 15.8 F.
abs(9 - n) which is 9 - n if 9 ≥ n and n- 9 if 9 ≤ n
158 degrees Fahrenheit equals 70 degrees Celsius. Here are the conversion formulae: TF = (9/5)*TC + 32 TC = (5/9)*TF - 32
85.8222oC Tf = (9/5)*Tc+32
The way to write out the difference of 9 and a number is n-9.
It is an equation: n - 9 = 9It is an equation: n - 9 = 9It is an equation: n - 9 = 9It is an equation: n - 9 = 9
It's easy to convert from Celsius to Fahrenheit by yourself. Tf = (9/5)*Tc+32, where Tc = temperature in degrees Celsius, Tf = temperature in degrees Fahrenheit. 9 C is -36 F.
Define the time (in days) taken by each person as: TA, TB and TC. In one day, A, B and C can respectively complete the following proportions of the work: 1/TA, 1/TB and 1/TC So together, they complete 1/TA + 1/TB + 1/TC of the work. It follows that they take 1 / [1/TA + 1/TB + 1/TC] days to complete the job together. So we can write * 6 = 1 / [1/TA + 1/TB + 1/TC] And by similar arguments: * 9 = 1 / [1/TB + 1/TC] * 8 = 1 / [1/TA + 1/TC] Solve the three equations simultaneously: * 1/6 = 1/TA + 1/TB + 1/TC * 1/9 = 1/TB + 1/TC subtracting yields 1/6 - 1/9 = 1/TA 1/TA = 1/18 * 1/9 = 1/TB + 1/TC * 1/8 = 1/18 + 1/TC subtracting yields 1/8 - 1/9 = 1/18 - 1/TB 1/TB = 1/9 - 1/8 + 1/18 = 3/72 = 1/24 and finally 1/TC = 1/8 - 1/18 = 5/72 Thus: TA = 18, TB = 24, TC =72/5.
For n+9=18, the answer would be n=9 because n+9=18 also mean 18-9=n so 18-9=9