Draw incircle and circumcircle. radius of incircle = 6 radius of circumcircle = 6 × 2/√3 = 12/√3 (side opposite to 60° is √3/2 times hypotenuse. consider right angled triangle formed by these two radius and 1/2 side of hexagon. (1/2 side)² = (12/√3)² - 6² = 12 1/2 side = √12 full side of hexagon = 2√12, perimeter = 12√12 Area = 1/2 a × perimeter = 1/2 × 6 × 12√12 = 36√12 = 72√3 unit²
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Easy. Since the side is the base and the apothem is the height of the triangle, multiply them and divide by two to get the area of the triangle. 3 * 3.46 = 10.38 /2 = 5.19. Then multiply by 6 to get the area of the hexagon. 5.19 * 6 = 31.14. You multiply by 6 because you can fit 6 regular triangles in a regular hexagon. We've already found the area of one regular triangle in the hexagon.
Let s be the length of a side of the hexagon and let h be the the apothem 6(1/2sh) it the area of 3sh.
The area is about 2338.27 square units, from the formulaA = 3/2 (sqrt 3) s2 or about 2.598 s2--Let's draw a segment from the center of the hexagon to the middle of a side. This segment is called the apothem. Then use the 30-60-90 triangle rule. If half of a side is 15, that means the apothem is 15√3.If we divide the hexagon into equilateral triangles, we get 6 equilateral triangles.So if we find the area for one of these triangles and multiply it by 6, we get the area of the hexagon. The area of a triangle is found by 1/2(b*h). The apothem is your height for the triangles. So plug the numbers in: 1/2(30*15√3). Solve: 1/2(779.4228) = 389.7114. This is the area of one triangle. Now we multiply by 6, and this becomes: 2338.2686
We don't need the measure of the radius since we know the measure length of the side and of the apothem, which we use to find the area of one of the triangles that are formed by connecting the center with the vertices of the hexagon. So, A = 6[(1/2)(11 x 9)] = 297 m2
If it's a regular hexagon then 6*27 = 162 cm