If x = sin θ and y = cos θ then: sin² θ + cos² θ = 1 → x² + y² = 1 → x² = 1 - y²
The domain of f(x)=3sin(2x) is all real numbers ----Any number can be input into this function and receive a valid output The range of f(x)=3sin(2x) is [-3,3] ----The range of y=sin(x) is [-1,1] frequency modulation, which happens when the argument of a sine function is modified, does not affect the range of a cosine or sine function, so the range of y=sin(2x) is also [-1,1]. Amplitude modulation, which happens when the entire function is multiplied by a numerical constant, does affect the range. If any number put into y=sin(2x) will output a maximum of 1, the most an input can cause in y=3sin(2x) will be 3 times the maximum of y=sin(2x), and the same for the minimums, so the range of y=3sin(2x) is from -3 to 3. If you would like a more complete explanation of the concepts underlying domain and range of functions, message me and I can more completely explain them.
The diagram should be divided into to parts, the domain and the range. The domain is those things that you put into the possible function and the range is what comes out. Let's call a member of the domain x and of the range y. You can tell it is a function by tracing from each x to each y. If there is only one y for each x; there is only one arrow coming from each x, then it is function!
The domain of a function determines what values of x you can plug into it whereas the range of a function determines the values that are your results. Therefore, look at the y-axis if you want to determine the range of a function and look at the x-axis if you want to determine the domain.
If f(x)=y, then the inverse function solves for y when x=f(y). You may have to restrict the domain for the inverse function to be a function. Use this concept when finding the inverse of hyperbolic functions.
y = sin(x)
Domain (input or 'x' values): -∞ < x < ∞.Range (output or 'y' values): -2 ≤ y ≤ 2.
The range of -sin x depends on the domain of x. If the domain of x is unrestricted then the range of y is [-1, 1].
Y=sin X is a function because for each value of X, there is exactly one Y value.
y = 3 sin x The period of this function is 2 pi.
x is a member of the function's domain, y is a member of the function's range.
The formula for ( 2\sin(x)\cos(x) ) is equivalent to ( \sin(2x) ) using the double angle identity for sine function.
Give the domain for
If you reflect a function across the line y=x, you will have a graph of the inverse. For trigonometric problems: y = sin(x) has the inverse x=sin(y) or y = sin-1(x)
#include double y, x;y= sin (x);
If x = sin θ and y = cos θ then: sin² θ + cos² θ = 1 → x² + y² = 1 → x² = 1 - y²
If I understand you correctly, yes. Normally we write y=sin(x) or y=cos(x), and because we make our x-axis run horizontally and our y-axis run vertically, this gives us a wave running left-to-right. If instead we wrote x=sin(y) or x=cos(y), the waves would run bottom-to-top. However, notice that in the first case, y is a function of x, but in the second case, x is a function of y. If we wished to make x=sin(y) or x=cos(y) into a function of x, we need to restrict the values of y in the domain so that it will pass the vertical line test. These "restricted" functions have a name, namely arcsin and arccos, and they are referred to as the inverse trigonometric functions.