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Find four consecutive odd integers such that the sum of the first three exceeds the fourth by 18?
Wiki User
∙ 14y ago
We have three consecutive odd integers, To make it easy, I am going to choose the one in the middle to be called X. Therefore, the first odd integer will be called (X-2) and the third odd integer will be called (X+2). The fourth odd integer will be called (X+4).
So the sum of the first three, is (X-2) + (X) + (X+2) or X+X+X -2 +2 this equals 3X.
Then, 3X -18 equals the fourth odd integer which is (X+4), so 3X - 18 = X + 4
Subtract an X from each side for 2X - 18 = 4. Add 18 to each side for 2X = 22. Solve for X, X equals 11. So the first consecutive odd integer is 11-2 or 9, the third is 11+2 or 13 and the fourth is X + 4 or 15. To Check, 9 + 11 + 13 = 33. 15 + 18 = 33
Wiki User
∙ 14y ago
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Find the smallest of four consecutive even integers if twice the sum of the second and third integers is equal to the sum of the first and fourth integers increased by fourteen?
Since we know that the integers are even and consecutive, we can call them x, x+2, x+4, and x+6, with x being the smallest of the four. twice the sum of the second and third can be written as 2(x+2+x+4)=4x+12 the sum of the first and fourth increased by 14 is x+x+6+14=2x+20 Then we can solve 4x+12=2x+20-->2x=8-->x=4 4
The sum of two consecutive integers is -377 What are the integers?
Consecutive means one after another.If the first is a, then the second is a+1.The sum of these isa + a + 1 = 2a+1 = -3772a = -378a = -189So the two numbers are -189 and -188
If the sum of the first two of the five consecutive odd integers is 52what is the sum of the last two integers?
Let the first odd integer be x, then the second one is x + 2. So we have: x + (x + 2) = 52 2x + 2 = 52 subtract 2 to both sides 2x = 50 divide by 2 to both sides x = 25 Thus, the first number is 25. Since consecutive odd integers grow by 2, then the second is 27, the third is 29, the fourth is 31, and the fifth integer is 33. So the sum of the last two integers is 64 ( 31 + 33).
If the sum of the first two of the five consecutive odd integers is 52 what is the sum of the last two integers?
(2x - 1) + (2x + 1) = 524x = 52x = 13The first 2 of 5 consecutive odd integers are 25 and 27.(Check: 25 + 27 = 52 yay!)The last 2 of 5 are 31 and 33.Their sum is 64.
How do you find consecutive integers?
Consecutive integers could be thought of as counting numbers in a row. One of them is "lowest" and the next one will be one more than that, and the last one will be one more than the second one. The numbers 7, 8 and 9 and 46, 47 and 48 are each said to be three consecutive integers. You often come across a question that tells you that 3 consecutive integers add up to a value. Example 3 consecutive integers add to 6. What are the integers? Let the first integer be x the second is then x +1 the third x+2 add them x+x+1+x+2 =3x+3 and this would be equal to 6. we then have the equation 3x+3=6 3x=3 x=1 so the first integer is 1, the second would be 2 and the third 3
What are the 2 consecutive integers such that the sum of one-third the first and one-fourth the second is 9?
-7
Find Four consecutive integers such that 8 times the sum of the first and the third is 40 greater than 10 times the fourth?
9,10,11,12
What is the sum of the first four non-negative consecutive even integers?
The sum of the first four non-negative, consecutive, even integers is 20.
Find four consecutive integers such that the sum of the second and fourth is 132 show the work?
Let the first consecutive integer be x. So that:the second integer is x + 1,the third integer is x + 2, andthe fourth integer is x + 3.We have:(x + 1) + (x + 3) = 1322x + 4 = 1322x = 128x = 64 the first integerThus, the four consecutive integers are 64, 65, 66, and 67.
The sum of 3 consecutive even integers is 54 What is the first consecutive integer?
The first integer is 17.
The sum of 4 consecutive integers is 182 What is the first integer?
The first integer is 44.
What are the three consecutive integers if the sum of the second and thrid exceeds a half of the first by thirty-three?
Let the three consecutive integers be n, n + 1 and n + 2. Then (n + 1) + (n + 2) = n/2 + 33 2n + 3 = n/2 + 33 : 4n + 6 = n + 66 : 3n = 60 : n = 20 The three numbers are 20, 21 and 22.
What consecutive prime integers have a difference of 20?
The first two consecutive prime numbers that have a difference of 20 are the numbers 887 and 907.
Find the smallest of four consecutive even integers if twice the sum of the second and third integers is equal to the sum of the first and fourth integers increased by fourteen?
Since we know that the integers are even and consecutive, we can call them x, x+2, x+4, and x+6, with x being the smallest of the four. twice the sum of the second and third can be written as 2(x+2+x+4)=4x+12 the sum of the first and fourth increased by 14 is x+x+6+14=2x+20 Then we can solve 4x+12=2x+20-->2x=8-->x=4 4
What is the sum of four consecutive even integers is 2 more than five times the first integer?
The integers would begin with 10.
Find three consecutive odd positive integers so that the product of the first two is three less than six times the largest?
The 3 consecutive odd positive integers are 7, 9 and 11.
The sum of two consecutive even integers is 50 what is the first number?
24. The second is 26.
