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If the sum of the first two of the five consecutive odd integers is 52what is the sum of the last two integers?
Let the first odd integer be x, then the second one is x + 2. So we have:
x + (x + 2) = 52
2x + 2 = 52 subtract 2 to both sides
2x = 50 divide by 2 to both sides
x = 25
Thus, the first number is 25. Since consecutive odd integers grow by 2, then the second is 27, the third is 29, the fourth is 31, and the fifth integer is 33.
So the sum of the last two integers is 64 ( 31 + 33).
What else can I help you with?
If the sum of the first two of the five consecutive odd integers is 52 what is the sum of the last two integers?
(2x - 1) + (2x + 1) = 524x = 52x = 13The first 2 of 5 consecutive odd integers are 25 and 27.(Check: 25 + 27 = 52 yay!)The last 2 of 5 are 31 and 33.Their sum is 64.
What are the Five consecutive odd integers starting with negative three?
-3, -1, 1, 3, 5
Five consecutive odd integers starting with -3?
There are two ways to approach this. You could use odd integers larger or smaller than -3. If you go larger than -3, the answer is: -3, -1, 1, 3, 5. If you go smaller than -3, the answer is: -3, -5, -7, -9, -11.
What are five consecutive integers whose sum is 170?
Let the five consecutive intgers be , n, n+1, n+2, n+3, ^ n +4 Summing n + (n+1) + (n+2) + (n+3) + (n +4) = 170 Hence 5n + 10 = 170 5n = 160 n = 160/5 n = 32 Hence the five consecutive intgers are: 32,33,34,35, & 36
Five times the sum of three consecutive integers is 150 what are the integers?
Let x=1st integer x+1=2nd integer x+2=3rd integer 5(x+x+1+x+2)=150 5(3x+3)=150 15x+15=150 15x=135 x=9 So you put what x is 1st integer (x)= 9 Since it's three consecutive integers, you add one to the 2nd integer 2nd integer (x+1)= 10 Then you do the same thing for the third integer 3rd integer (x+2)= 11
What is the sum of four consecutive even integers is 2 more than five times the first integer?
The integers would begin with 10.
What is a set of five consecutive integers that are all composite?
4,6,8,9,10
When the smaller of two consecutive integers is added to five times the larger the result is 65?
The integers are 10 and 11.
What is the greatest of 5 consecutive integers if the sum of these integers equals -45?
50
Five consecutive integers starting with 6?
-6, -5, -4, -3 and -2.
If the sum of the first two of the five consecutive odd integers is 52 what is the sum of the last two integers?
(2x - 1) + (2x + 1) = 524x = 52x = 13The first 2 of 5 consecutive odd integers are 25 and 27.(Check: 25 + 27 = 52 yay!)The last 2 of 5 are 31 and 33.Their sum is 64.
If five consecutive numbers have a sum of 360 what is the value of the greatest integer?
The value of the greatest integer is 76. This occurs when the set of five consecutive integers is all even numbers.
Five times the first of three consecutive even integers is 14 more then 3 times the second?
Three consecutive even integers can be represented by a-2, a & a+2.Five times the first is 5a-10. Three times the second is 3a.5a-10 is 14 more than 3a, so 5a-10 = 3a+14Adding 10 to both sides: 5a = 3a+24Taking 3a from both sides: 2a = 24Therefore a=12The three consecutive even integers are 22, 24 and 26.
Five times the smallest of three consecutive even integers is 10 more than twice the largest. find the integers?
5872345098234783904672083946728390752430689723409687298290843 theres your answer
What are five consecutive integers have a sum of 0?
The numbers are -2, -1, 0, 1 and 2.
The sum of ten consecutive integers is five what is the largest of these integers?
Well, well, well, look who's trying to do some math! If the sum of ten consecutive integers is five, then the middle number is 0. So, the largest integer would be 4. Keep crunching those numbers, honey!
What are three consecutive integers such that the sum of five times the first six times the second and seven times the third is 148?
This doesn't work for integers. Using 7, 8 and 9 comes up with 146 which is the closest you can get.
