Firstly you need to work out the length of a side.
Using Pythagorean Theorem for a right angled triangle
a2+b2=c2 where a = the length, b = height & c = diagonal
since c = 8 and a = b are the same
2a2 = 64
a2 = 32
a = 5.657 cm
since the area of the square is a2 then area = 32cm2
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The length of the diagonal of a square whose side lengths are 7 square root 2 (9.89949494) is: 14 units.
a≈2.83cm The sides are the square root of 8 cm, approximately 2.8284 cm
area - width = length
The diagonal of a 46' x 46' square is 65.05 feet.
Using Pythagoras' theorem the length of the diagonal is 20 feet