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Distance between (0,0) and (8,2): √((8-0)2+(2-0)2) = √(82+22) = √(64+4) = √(68) = 2√17 ~= 8.246
The distance between the points of (2, 3) and (7, 0) is the square root of 34
To find the distance between the origin and the point (x,y) use Pythagoras on the right angled triangle which has the points (0, 0), (x, 0), (x, y) - the distance is the hypotenuse of the triangle and so has length: distance = √(x2 + y2) This can be extended to find the distance between any two points (x1, y1) and (x2, y2): distance = √((x2 - x1)2 + (y2 - y1)2) (for the original question (x1, y1) is the origin (0, 0) and the first formula results.)
-2 & 5
The distance between two points on a coordinate plane is calculated using the distance formula: Distance = √((x2 - x1)^2 + (y2 - y1)^2) In this case, the coordinates of the two points are (7, 1) and (7, 3). Since the x-coordinates are the same, we only need to calculate the difference in the y-coordinates, which is (3 - 1) = 2. Plugging this into the distance formula gives us: Distance = √((0)^2 + (2)^2) = √4 = 2. Therefore, the distance between the two points is 2 units.