I'm assuming that these are 3-D coordinates A(0,0,0) and B(3,4,5) The distance formula between two points in 3 dimensions is the following: D = SQR {(x1-x2)2 + (y1-y2)2 + (z1-z2)2} D = SQR {(0-3)2 + (0-4)2 + (0-5)2} D = SQR {9+16+25} = SQR {50} D is approx. = 7.07
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Points: (-6, 1) and (-2, -2) Distance: 5 units
(3-1)2 + (5-8)2 = 13 and the square root of this is the distance between the points
The sq.root of 122+162=20
Points: (0, 0) and (2, 6) Slope: 3
If d is the distance between them, then d2 = (-6 -10)2 + (1 - (-8))2 = (-16)2 + 92 =256 + 81 = 337 so d = sqrt(337) = 18.36