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I'm assuming that these are 3-D coordinates A(0,0,0) and B(3,4,5) The distance formula between two points in 3 dimensions is the following: D = SQR {(x1-x2)2 + (y1-y2)2 + (z1-z2)2} D = SQR {(0-3)2 + (0-4)2 + (0-5)2} D = SQR {9+16+25} = SQR {50} D is approx. = 7.07
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What is the distance between points (-6 1) and (-2 -2)?
Points: (-6, 1) and (-2, -2) Distance: 5 units
What is the distance between the points 3 5 and 1 8?
(3-1)2 + (5-8)2 = 13 and the square root of this is the distance between the points
Find the distance between the points -2 -10 and 10 6?
The sq.root of 122+162=20
What is the slope of the line through the points (0 0) and (2 6)?
Points: (0, 0) and (2, 6) Slope: 3
Find the distance between points -6 1 and 10 -8?
If d is the distance between them, then d2 = (-6 -10)2 + (1 - (-8))2 = (-16)2 + 92 =256 + 81 = 337 so d = sqrt(337) = 18.36
What is the the distance between the points (2 4) and (5 0)?
Points: (2, 4) and (5, 0) Distance: 5
Find the distance between the points -2 2 and -2 2?
0 0
What is the distance between points A 2 3 2 and B 0 0 0?
7
What is the distance between the points 2 and 4 and 5 and 0?
-2 & 5
What is the distance between the points -2 0 and -1 -1?
Answer: 1
What is the distance between the points -2 2 and -2 2?
0 is the answer. If you start at -2 2, and end at -2 2, you moved 0 spots so there is no distance.
What is the distance between points (23) and (70) to the nearest tenth?
The distance between the points of (2, 3) and (7, 0) is the square root of 34
What is the distance between these two points 0 0 and 8 2?
Distance between (0,0) and (8,2): √((8-0)2+(2-0)2) = √(82+22) = √(64+4) = √(68) = 2√17 ~= 8.246
What is the distance between the two points 2 3 and 0 -2?
The square root of (2x2)+(5x5) is 5.385164807134504 ' . . . . . . .
What is the distance between points (0 0) and (-2 -2)?
It works out as the square root of 8 which is about 2.828 rounded to 3 decimal places
Find the distance between (-4 2) and (-7 -6). in units?
The distance between the points of (4, 3) and (0, 3) is 4 units
What is the taxi distance between the points 0-0 and 5-2?
Using Pythagoras: 5 squared + 2 squared = √21 which is about 4.58.
