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First find the slope 'm'
m = ( y(1) - y(2))/ (x(1) - x(2))
Hence
m = ( -3 - - 63) / ( -76 - 7)
m = 60/ -83 = -60/83
Hence
y = (-60/83)x + c
To find 'c' take either point and displace against x & y.
Hence
y - - 3 = ( -60/83) (x - -76)
y + 3 = (-60/83) ( x + 76)
Multiply through by '83'.
Hence
83y + 249 = -60x - 4560
83y = -60x - 4809
or
60x + 83y = -4809
or
60x + 83y + 4809 = 0
I'm assuming the points are (-76, -3) and (7, -63). If that's the case then the equation can be found by the following. (1) First find the slope of a line between these two point, m: m = (y1 - y2)/(x1 - x2) = (-3 - -63) / (-76 - 7) = - 60/83 (2) The equation for a line is y = mx + b, since we have the slope m already, use one of the points listed to solve for the intercept b. (I used the first one: -76, -3) -3 = -60/83*(-76) + b -3 = 4560/83 + b b = -4809/83 So the equation of the line joining these two point is: Y = (-60/83)X - (4809/83)
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yes because you will need the slope and y-intercept to find the equation of a line and the point through which the line passes is the y-intercept so it is yes!!!!!!! Good Luck!!!!!!!!!!!!!
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