It is negative 3x^2.
2
-2/15 or pronounced negative two fifteenths
Y = 2/3X - 3 you know Y, 0 out Y to find X intercept 2/3X - 3 = 0 2/3X = 3 X = 9/2 a line between Y = -3 and X = 9/2 comes from the 3rd quadrant, through the 4th quadrant and into the first
x^2 + 3x + 2/(-3x) - x^2 - 2=3x-2+2/(-3x)=3x-2-2/(3x)
It is negative 3x^2.
-(3x -2) = 17 -3x + 2 = 17 - 3x = 15 x = -5
-1/6 * 3x = -3x/6 = -x/2
x is negative 1x is negative 2
2
The equivalent expression of 3x-9 plus 3x plus 5 is negative 4.
As we divide a positive by negative sign then the result also has negative sign. When we add we get 3x + 10. Then dividing by - 5, then it becomes - 3x/5 - 2.
1 = -2/3x Multiply both sides by x x = -2/3
negative 2
3x+4y = 8 4y = -3x+8 y = -3/4x+2 in slope intercrpt form It has a negative slope so the straight line goes 'downhill'
-2/15 or pronounced negative two fifteenths
You can do this by finding two numbers whose product is equal to the product of the coefficients on the first and last terms, and whose sum is equal to the coefficient of the middle term. So we want two numbers, call them A and B, that add to make 3 and multiply to make -2 * 9, or -18. Those numbers would be six and negative three. You can take those numbers and break the middle term down into two terms using them as their coefficients: 9x2 + 3x - 2 = 9x2 + 6x - 3x - 2 Now factor out like terms: = 3x(3x + 2) - 1(3x + 2) And group: = (3x - 1)(3x + 2)