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x2+8x = -3x2+5 4x2+8x-5 = 0 (2x+5)(2x-1) = 0 x = -5/2 or x = 1/2
Assuming the 2 is meant to be a square this is the form: x2 - 3x2 = -2x2 + 8x + 5
3x2 + 2x = 16 ∴ 3x2 + 2x - 16 = 0 ∴ 3x2 - 6x + 8x - 16 = 0 ∴ 3x(x - 2) + 8(x - 2) = 0 ∴ (3x + 8)(x - 2) = 0 ∴ x ∈ {-8/3, 2}
The answe is 27x^4 + 6x^3 - 61x^2 - 68x - 42
Factors are (3x + 2)(x + 2) so x is either -2/3 or -2 If term in x is negative then factors are (3x - 2)(x - 2) and solutions are 2/3 and 2.