If you know the values of "f" and "x", you just do the multiplication.Please note that if you see something like:
y = f(x)
this usually does NOT mean that f and x should be multiplied; it means that "y" SOMEHOW depends on "x", i.e., it is a function of "x". To calculate the value of this function, you need to know how exactly the function is defined.
f times x equals fx
The substitute of F in the equation F times 2 X times 3 X would be 0. This is taught in math.
d[fg(x)]/dx = df(x)/dx*g(x) + f(x)*dg(x)/dx or (fg)' = f'g + fg'
6 * x2 = 6x2
Even polynomial functions have f(x) = f(-x). For example, if f(x) = x^2, then f(-x) = (-x)^2 which is x^2. therefore it is even. Odd polynomial functions occur when f(x)= -f(x). For example, f(x) = x^3 + x f(-x) = (-x)^3 + (-x) f(-x) = -x^3 - x f(-x) = -(x^3 + x) Therefore, f(-x) = -f(x) It is odd
"First principles" in this context means that you:* Calculate the value of the function, at some point "x+h" * Calculate the value of the function, at some point "x" * Subtract the first result minus the second result * Divide all this by "h" * See what happens when you make "h" smaller and smaller (when it tends to zero) As a formula: F(x)' = lim (as h --> 0) [F(x+h) - F(x)] / h
Select a set of values for x. For each value calculate the value of f(x). On a graph paper, mark the points [x, f(x)].
∫ [f'(x)g(x) - g'(x)f(x)]/[f(x)g(x)] dx = ln(f(x)/g(x)) + C C is the constant of integration.
e^(-2x) * -2 The derivative of e^F(x) is e^F(x) times the derivative of F(x)
Substitute the value 3 for x in the expression for f(x) and then calculate its value.
To calculate volume simply do length x width x height
The substitute of F in the equation F times 2 X times 3 X would be 0. This is taught in math.
Temperature C times 1.8+32=Temperatur F. Example- 25C to F 25C X 1.8 = 45, 45+32=77F
∫ [f'(x)g(x) - f(x)g'(x)]/(f(x)2 - g(x)2) dx = (1/2)ln[(f(x) - g(x))/(f(x) + g(x))] + C
∫ [f'(x)g(x) - f(x)g'(x)]/(f(x)2 + g(x)2) dx = arctan(f(x)/g(x)) + C C is the constant of integration.
Wherever there is an x substitute -2 and calculate the resulting sum: f(x) = 3x² - x → f(-2) = 3 × (-2)² - (-2) = 3 × 4 + 2 = 12 + 2 = 14
The only "formula" is 54741155041/9 However, you can calculate the value iteratively, using the Newton-Raphson method as follows: Define f(x) = x9 - 547411504 and solve for f(x) = 0 The first derivative is f'(x) = 9*x8 So take a guess at x, say x0. Calculate x1 = x0 - f(x0)/f'(x0) Continue: calculate x2 = x1 - f(x1)/f'(x1). If you started with a reasonably good estimate you will find that the the estimates converge to the answer. In this case, the answer is 12.079 (approx).
∫ f'(x)/(af(x)2 + bf) dx = (1/b)ln[f(x)/(af(x) + b)] + C C is the constant of integration.