To calculate f times x, you simply multiply the value of f by the value of x. This can be represented as f * x. For example, if f = 5 and x = 10, then f times x would be 5 * 10 = 50. Multiplication is a basic arithmetic operation that involves repeated addition and is essential in various mathematical calculations.
If you know the values of "f" and "x", you just do the multiplication.Please note that if you see something like:
y = f(x)
this usually does NOT mean that f and x should be multiplied; it means that "y" SOMEHOW depends on "x", i.e., it is a function of "x". To calculate the value of this function, you need to know how exactly the function is defined.
The substitute of F in the equation F times 2 X times 3 X would be 0. This is taught in math.
The expression fxfxf means f(f(x)f(x)), where f(x) is a function of x. This is not equivalent to f cubed (f^3(x)), which would mean f(f(f(x))). In fxfxf, the function f(x) is applied twice to the input x, whereas in f cubed, the function is applied three times. The two expressions are different due to the number of times the function is applied to the input.
d[fg(x)]/dx = df(x)/dx*g(x) + f(x)*dg(x)/dx or (fg)' = f'g + fg'
Even polynomial functions have f(x) = f(-x). For example, if f(x) = x^2, then f(-x) = (-x)^2 which is x^2. therefore it is even. Odd polynomial functions occur when f(x)= -f(x). For example, f(x) = x^3 + x f(-x) = (-x)^3 + (-x) f(-x) = -x^3 - x f(-x) = -(x^3 + x) Therefore, f(-x) = -f(x) It is odd
"First principles" in this context means that you:* Calculate the value of the function, at some point "x+h" * Calculate the value of the function, at some point "x" * Subtract the first result minus the second result * Divide all this by "h" * See what happens when you make "h" smaller and smaller (when it tends to zero) As a formula: F(x)' = lim (as h --> 0) [F(x+h) - F(x)] / h
Select a set of values for x. For each value calculate the value of f(x). On a graph paper, mark the points [x, f(x)].
∫ [f'(x)g(x) - g'(x)f(x)]/[f(x)g(x)] dx = ln(f(x)/g(x)) + C C is the constant of integration.
e^(-2x) * -2 The derivative of e^F(x) is e^F(x) times the derivative of F(x)
The substitute of F in the equation F times 2 X times 3 X would be 0. This is taught in math.
To calculate volume simply do length x width x height
Substitute the value 3 for x in the expression for f(x) and then calculate its value.
Temperature C times 1.8+32=Temperatur F. Example- 25C to F 25C X 1.8 = 45, 45+32=77F
∫ [f'(x)g(x) - f(x)g'(x)]/(f(x)2 - g(x)2) dx = (1/2)ln[(f(x) - g(x))/(f(x) + g(x))] + C
∫ [f'(x)g(x) - f(x)g'(x)]/(f(x)2 + g(x)2) dx = arctan(f(x)/g(x)) + C C is the constant of integration.
The expression fxfxf means f(f(x)f(x)), where f(x) is a function of x. This is not equivalent to f cubed (f^3(x)), which would mean f(f(f(x))). In fxfxf, the function f(x) is applied twice to the input x, whereas in f cubed, the function is applied three times. The two expressions are different due to the number of times the function is applied to the input.
Wherever there is an x substitute -2 and calculate the resulting sum: f(x) = 3x² - x → f(-2) = 3 × (-2)² - (-2) = 3 × 4 + 2 = 12 + 2 = 14
The only "formula" is 54741155041/9 However, you can calculate the value iteratively, using the Newton-Raphson method as follows: Define f(x) = x9 - 547411504 and solve for f(x) = 0 The first derivative is f'(x) = 9*x8 So take a guess at x, say x0. Calculate x1 = x0 - f(x0)/f'(x0) Continue: calculate x2 = x1 - f(x1)/f'(x1). If you started with a reasonably good estimate you will find that the the estimates converge to the answer. In this case, the answer is 12.079 (approx).