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2y2 + 9y - 2 this will not factor using integers what is what most algebra teachers will tell you is 'prime'
but ... make an equation ... 2y2 + 9y - 2 = 0
use the quadratic formula to solve
y = [-9 (+/-) sq rt (81 -4x2(-2))] / (2x2)
y = [-9 (+/-) sq rt (97)] / (4) now separate these
y = [-9 + sq rt (97)] / (4)
y = [-9 - sq rt (97)] / (4) rewrite as equal to zero
(y - [-9 + sq rt (97)] / (4)) =0
(y - [-9 - sq rt (97)] / (4)) = 0 apply zero product property in reverse
(y - [-9 + sq rt (97)] / (4))(y - [-9 - sq rt (97)] / (4)) = 0
these, as weird as they may look, are the factors.
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