If the missing sign is minus then you have the difference of two squares so:
(2x + 3y)(2x - 3y)
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4x2+2x+1
Factor the equation and solve for x in each part. x3-4x2-12x Factor out an x right away x (x² - 4x - 12) factor the trinomial x (x - 6) (x + 2) now solve each for y=0 x=0, (x-6=0), (x+2=0) The zeroes (solutions) to the equation are {-2 0 6 }■
16 - a2
4x2 - 30 = 34 ⇒ 4x2 = 64 ⇒ x2 = 16 ⇒ x = 4 or -4
use the difference of two squares yule.