(2y)(2x - 3z)
Factorise fully is when brackets are involved in the equation
m(g-a)
In the same way that you would factorise any other expressions that do not contain an equality sign depending on the expressions of which none have been given.
5(3-2x)
(2y)(2x - 3z)
If you aren't dealing with algebra, such as x2+3x+21, then completing the square wont be able to solve the porblem, however if you are using algebra, and you cannot factorise, then completing the square will always work
Factorise fully is when brackets are involved in the equation
a²-a = a(a-1)
To factorise is to find the numbers that divide into the original number by only using prime numbers. For example factorise 20 = 2 times 2 times 5
to put into brackets
you do (245x)
The answer will depend on where the brackets are. In general the solution would be to expand all the brackets, combine like terms and then factorise.
You need to spot that 16x2 is the square of 4x and that 225 is the square of 15. Notice that the expression is a "difference of 2 squares", which is a standard result in algebra a2 - b2 = (a + b)(a - b) so here we factorise to (4x + 15)(4x - 15)
6(t2s)
m(g-a)
-5