not sure 100% but my dad told me:
e.g. 2(3x + 4)
2 x 3x = 6x
2 x 4 = 8
so its
6x + 8
another one is
x(7x + x^2)
x times 7x = 7x^2
x times x^2 = x^3
so its
7x^2 + x^3
PS. the ^2 and ^3 stands for sqaured and cubed (:
(2y)(2x - 3z)
Ah, let's take a moment to appreciate the beauty of algebra. To factorise 6ab - 9ac, we can first factor out the greatest common factor, which is 3a. This leaves us with 3a(2b - 3c), where 2b - 3c is the factored expression. Just like painting a happy little tree, we've simplified our expression with a few gentle brushstrokes.
m(g-a)
In the same way that you would factorise any other expressions that do not contain an equality sign depending on the expressions of which none have been given.
5(3-2x)
(2y)(2x - 3z)
If you aren't dealing with algebra, such as x2+3x+21, then completing the square wont be able to solve the porblem, however if you are using algebra, and you cannot factorise, then completing the square will always work
a²-a = a(a-1)
To factorise is to find the numbers that divide into the original number by only using prime numbers. For example factorise 20 = 2 times 2 times 5
Ah, let's take a moment to appreciate the beauty of algebra. To factorise 6ab - 9ac, we can first factor out the greatest common factor, which is 3a. This leaves us with 3a(2b - 3c), where 2b - 3c is the factored expression. Just like painting a happy little tree, we've simplified our expression with a few gentle brushstrokes.
you do (245x)
to put into brackets
The answer will depend on where the brackets are. In general the solution would be to expand all the brackets, combine like terms and then factorise.
6(t2s)
It is the opposite of Expanding The Brackets
-5
m(g-a)