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How do you find the equation of a parabola with x intercepts -1 and 3 and y intercept 8?
Wiki User
∙ 14y ago
Steps
1) Find the co-ordinates of the vertex, by adding the x-intercepts and dividing by 2.
Xv= (-1+3) / 2
This gives you the x-coordinate of the vertex, 1. The vertex of the parabola is at (1, 8)
2) Sub into the vertex form equation. (y= a(x-h)2+k h = x coord of vertex, k = y coord
y=a(x-1)2+8
note: when subbing in x value, always put the reverse sign into the equation, if positive, sub it in as negative, if negative, sub in as positive
Now you can't solve for a without knowing what point is passes through on the y-axis. after you know that you just solve sub x and y in, solve for a, then put a into the equation
ex: y= 2(x-1)2+8
Wiki User
∙ 14y ago
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