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How do you find the equation of a parabola with x intercepts -1 and 3 and y intercept 8?
Steps
1) Find the co-ordinates of the vertex, by adding the x-intercepts and dividing by 2.
Xv= (-1+3) / 2
This gives you the x-coordinate of the vertex, 1. The vertex of the parabola is at (1, 8)
2) Sub into the vertex form equation. (y= a(x-h)2+k h = x coord of vertex, k = y coord
y=a(x-1)2+8
note: when subbing in x value, always put the reverse sign into the equation, if positive, sub it in as negative, if negative, sub in as positive
Now you can't solve for a without knowing what point is passes through on the y-axis. after you know that you just solve sub x and y in, solve for a, then put a into the equation
ex: y= 2(x-1)2+8
What else can I help you with?
How do you find the x and y intercepts of a linear equation in standard form?
The y-intercept is c in the standard form. The x-intercept is -c/m.
Find the x and y intercept of 9x54-6y?
I believe that you need an equation to solve for the x and y intercepts.
How do you determine the intercepts from an equation or graph?
From the equation, the y intercept is simply determined by setting x = 0. The x intercept(s) are generally much harder to find: you will need to find the solutions of y = 0 [or f(x) = 0]. From the graph the intercepts are the coordinates of the points at which the graph crosses the axes.
How do you find the equation of a parabola in standard form with x intercepts at 0 and 0 passing through 7 and 8?
y = 8/49*x2
Find the equation of line passing through 3 6 and making intercepts equal in magnitude but opposite in sign?
A sample equation could be y = 5/3x + 1, the x-intercept is 1 and the y-intercept is -1.
How do you find the x-intercept of a parabola?
Factorise equation, and look at what x values are needed for the equation to equal zero. Eg. x^2+5x+6 (x+3)(x+2)=0 So parabola intercepts x axis at -3 and -2.
Find the x intercept or intercepts and the coordinates of the vertex for the parabola x2-4x-12 if there is more than one x intercept separate them with commas?
The x-intercept of an equation is any location where on the equation where x=0. In the case of a parabolic function, the easiest way to obtain the x intercept is to change the equation into binomial form (x+a)(x-b) form. Then by setting each of those binomials equal to zero, you can determine the x-intercepts.
How do you find the y intercept on a parabola?
If you know the equation, you just plug in x = 0 and solve.
Find the X and Y intercepts of 9 equals 3 y?
The equation 9=3y has the x-intercept (0,0) and the y-intercept (0,3).
How do you find the x and y intercepts of a linear equation in standard form?
The y-intercept is c in the standard form. The x-intercept is -c/m.
Find the x and y intercept of 9x54-6y?
I believe that you need an equation to solve for the x and y intercepts.
How do you find y and x intercept of parabola?
For the equation of any graph. The graph intercepts the y-axis, when x is zero, so in the equation, substitute x=0, and solve for y. To find the x-intercept, this is when y is zero, so substitute y=0, and solve for x. For a parabola, if the highest power of y is the 1st power (no exponent) and the highest power of x is 2, then the parabola opens up or down. The parabola will have 1 y-intercept (usually it is the constant value), and depending on where it is (if it is at the origin, it is also an x-intercept, and the other x-intercept has the same distance as y-intercept has from the axis of symmetry i.e y = a2x + bx), either have 2 x-intercepts, or no interceptions with the x-axis (i.e. y = x2 + c, c ≥ 0 or y = -x2 + c, c ≤ 0). If the highest power of y is 2, and highest power of x is 1, then it opens left or right, and it may have none or 2 y-intercepts, and will have 1 x-intercept. So when you're solving for the one that's a quadratic, if you come up with imaginary or complex roots, that means there is no intercept.
How do you factor and find the intercepts to the equation x3-8?
(x - 2)(x^2 + 2x + 4) The x-intercept is 2. The y-intercept is -8
How do you find the y intercept when given a parabola in standard form?
At any point on the y-axis, the x-coordinate is zero. In the equation of the parabola, set x=0. Tidy it up, and you have " Y = the y-intercept ".
How do you find the coordinants of a y-intercept and x-intercept?
To solve for intercepts on a straight line graph put the equation in the form y=mx+c where c is the y-intercept and you have the y intercept. Now to solve x-intercept set y=0 eg y=2x+5 0=2x+5 2x=-5 x=-2.5 For intercepts on other forms of graphs eg parabola y-intercept= make x equal to 0 and solve x-intercept= make y equal to 0 and solve
How do you determine the intercepts from an equation or graph?
From the equation, the y intercept is simply determined by setting x = 0. The x intercept(s) are generally much harder to find: you will need to find the solutions of y = 0 [or f(x) = 0]. From the graph the intercepts are the coordinates of the points at which the graph crosses the axes.
What are the intercepts of 6x 8y 24?
To find the intercepts of the equation (6x + 8y = 24), we can set (y = 0) to find the x-intercept: [ 6x = 24 \implies x = 4 ] Thus, the x-intercept is ((4, 0)). Setting (x = 0) to find the y-intercept gives: [ 8y = 24 \implies y = 3 ] So, the y-intercept is ((0, 3)). Therefore, the intercepts are ((4, 0)) and ((0, 3)).
