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A rhombus is a flexible shape which can range from almost a square to a very narrow shape. A rhombus with sides of x cm can contain a circle with any radius less than x/2 cm. The information in the question is insufficient to determine the radius. And a ratio requires some characteristic of the inscribed circle to be compared to an analogous characteristic of another shape.
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The diagonals of the rhombus are in the ratio 3 4 the perimeter of the rhombus is 40cm find the lengths of the sides and of the diagonals?
The length of the sides of the rhombus are 10cm, as a rhombus has equal sides. since the diagonals of a rhombus are perpendicular, ratio of side of rhombus to 1/2 a diagonal to 1/2 of another diagonal is 5:4:3 (pythagorean thriple), hence ratio of side of rhombus to 1 diagonal to another diagonal is 5:8:6. since 5 units = 10cm 8 units = 16cm 6 units = 12cm and there are your diagonals.
An isosceles right triangle is inscribed in a circle Find the radius of the circle if one leg of the triangle is 8 cm?
First you half all the sides, so 4cm, them you multiply by pi, giving the radius as 12pi, or 12.56637061
What is the ratio of the area of the circumscribed square to the area of the inscribed square?
If we denote the measure of the length side of the circumscribed square with a, then the vertexes of the inscribed square will point at the midpoint of the side, a, of the circumscribed square.The area of the circumscribed square is a^2The square measure of the length of the inscribed square, which is also the area of this square, will be equal to [(a/2)^2 + (a/2)^2]. Let's find it:[(a/2)^2 + (a/2)^2]= (a^2/4 + a^2/4)= 2(a^2)/4= a^2/2Thus their ratio is:a^2/(a^2/2)=[(a^2)(2)]/a^2 Simplify;= 2
How do you find the perimeter of a rhombus if the length of a side is 6?
The four sides of a rhombus are equal and so: 6+6+6+6 = 24
The triangle ABC is inscribed in a semicircle if ABC is 42degrees find A bac B acb?
90
