The x-intercept is the point where the line crosses the x-axis. 'y' is zero
at every point on the x-axis. So to find where the line crosses the x-axis,
make 'y' zero, and solve the equation for 'x'.
-- The y-intercept is the point where the line crosses the y-axis. 'x' is zero
at every point on the y-axis. So to find where the line crosses the y-axis,
make 'x' zero, and solve the equation for 'y'.
This is the central idea that the following answer calls "zero out".
=========================================================X and Y intercepts
1
y-intercept: -1/4 x-intercept: 1/5 5x-4y=1 -4y=-5x+1 y=5/4x+1/-4 5x-4y=1 5x=4y+1 x=4/5y+1/5
3x - 4y = 8Solve for x:3x = 4y + 8x = 4/3y + 8/3Solve for y:-4y = -3x + 8y = 3/4x - 2
3x + 4y = 5To find the x-intercept, let x = 03(0) + 4y = 54y = 5y = 5/4The line passes through (0, 5/4), so y-intercept is 5/4.To find x-intercept, let y = 03x + 4(0) = 53x = 5x = 5/3The line passes through (5/3, 0), so x-intercept is 5/3.Plot (0, 5/4) and (5/3, 0). Draw a straight line through them.Or,3x + 4y = 53x - 3x + 4y = 5 - 3x4y = -3x + 54y/4 = (-3x + 5)/4y = (-3/4)x + 5/4So the slope will be -3/4 and the y-intercept is 5/4; (0, 5/4)We find the x-intercept when y = 0, so0 = (-3/4)x + 5/40 - 5/4 = (-3/4)x + 5/4 - 5/4-5/4 = (-3/4)x(-5/4)/(-3/4) = [(-3/4)x]/(-3/4)5/3 = x ; (5/3, 0)Thus, the line passes through the points (0, 5/4) and (5/3, 0).
3x - 4y = 8Solve for x:3x = 4y + 8x = 4/3y + 8/3Solve for y:-4y = -3x + 8y = 3/4x - 2
3x - 4y = 24At the x-intercept, y=0 :3x = 24x = 8At the y-intercept, x=0 :-4y = 24y = -6
If you mean 3x+4y = 12 then the x intercept = 4 and the y intercept = 3
2x = 3x - 4y - 16 so 4y = x - 16 or y = x/4 - 4 Slope = 1/4 or 0.25 intercept = -16
-3x + 4y = 12∴ 4y = 3x + 12∴ y = 3x/4 + 3So this is a line with a slope of 3/4, an x-intercept of {0, 3} and a y-intercept of {-4, 0}
Just by inspection it looks like 4. Let's check. 3X + 4Y = 12 4Y = -3X + 12 Y = -3/4X + 3 0 out the Y -3/4X + 3 = 0 -3/4X = -3 X = 4 -------------is the X intercept
9x2 + 24xy + 16y2 = 9x2 + 12xy + 12xy + 16y2 = 3x(3x + 4y) + 4y(3x + 4y) = (3x + 4y)*(3x + 4y) = (3x + 4y)2
I'm assuming that the entire equation is 3x + 4y = 0Here the slope is -ve 3/4 and the intercept is 0.So, the slope intercept form is y = - 3x/4 or y = - (3/4)x
-3X + 4Y = -4 get equation in form y = mx +b m = slope b = intercept 4Y = 3X-4 Y = 3/4 X - 1 m = 3/4 b = -1
3x - 4y = 1Subtract 3x from each side:-4y = -3x + 1Multiply each side by -1:4y = 3x - 1Divide each side by 4:y = 3/4 x - 1/4The graph is a straight line with [ slope = 3/4 ] and [ y-intercept = -1/4 ].
3x-4y=40 (x=0) 3(0)-4y=40 -4y=40 y=40/-4 y=-10 x1 , y1 (13 , -10) (4y=0) 3x-4(0)=40 3x=40 x=40/3 x=13.33 or 13
First, write it out. 3x+4y=16 Now, I was taught to find the y intercept by using slope intercept form, so pardon me if I am donig it differently than the way you are used to :p You want to get the y on one side, alone, so subtract the x. 3x+4y=16 -3x ......-3x 4y=-3x+16 Now, you want the y to have no coefficient, therefore you divide EVERYTHING by 4. 4y=-3x+16 /4 ..../4 ....../4 y=-3/4x+4 Your y intercept is the lone number, hence "4".
3x=4y-x 4x=4y x=y