The x-intercept is the point where the line crosses the x-axis. 'y' is zero
at every point on the x-axis. So to find where the line crosses the x-axis,
make 'y' zero, and solve the equation for 'x'.
-- The y-intercept is the point where the line crosses the y-axis. 'x' is zero
at every point on the y-axis. So to find where the line crosses the y-axis,
make 'x' zero, and solve the equation for 'y'.
This is the central idea that the following answer calls "zero out".
=========================================================X and Y intercepts
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y-intercept: -1/4 x-intercept: 1/5 5x-4y=1 -4y=-5x+1 y=5/4x+1/-4 5x-4y=1 5x=4y+1 x=4/5y+1/5
3x - 4y = 8Solve for x:3x = 4y + 8x = 4/3y + 8/3Solve for y:-4y = -3x + 8y = 3/4x - 2
3x + 4y = 5To find the x-intercept, let x = 03(0) + 4y = 54y = 5y = 5/4The line passes through (0, 5/4), so y-intercept is 5/4.To find x-intercept, let y = 03x + 4(0) = 53x = 5x = 5/3The line passes through (5/3, 0), so x-intercept is 5/3.Plot (0, 5/4) and (5/3, 0). Draw a straight line through them.Or,3x + 4y = 53x - 3x + 4y = 5 - 3x4y = -3x + 54y/4 = (-3x + 5)/4y = (-3/4)x + 5/4So the slope will be -3/4 and the y-intercept is 5/4; (0, 5/4)We find the x-intercept when y = 0, so0 = (-3/4)x + 5/40 - 5/4 = (-3/4)x + 5/4 - 5/4-5/4 = (-3/4)x(-5/4)/(-3/4) = [(-3/4)x]/(-3/4)5/3 = x ; (5/3, 0)Thus, the line passes through the points (0, 5/4) and (5/3, 0).
3x - 4y = 8Solve for x:3x = 4y + 8x = 4/3y + 8/3Solve for y:-4y = -3x + 8y = 3/4x - 2