You move the graph upwards by 2 units.
y=x+1 there for answer is 2
x = 1 is a graph of a straight line that touches the x-axis at 1 and extends infinitely up and down.
graph gx is the reflection of graph fx and then transformed 1 unit down
y = x^2 - x - 2 This is the graph of a parabola. We need to find the x-intercepts. Set 0 for y, and solve for x: 0 = x^2 - x - 2 0 = (x + 1)(x - 2) x + 1 = 0 or x - 2 = 0 x = -1 or x = 2 Thus, x-intercepts are -1 and 2. The graph of y = x^2 - x - 2 crosses the x-axis at x = -1 and x = 2.
graph G(x)=[x]-1
When a function is multiplied by -1 its graph is reflected in the x-axis.
The graph of the function y(x) = 1/x is a hyperbola.
You move the graph upwards by 2 units.
The graphs of y = f(x) and y = a*f(x) when a = 1 are identical.
y=x+1 there for answer is 2
x = 1 is a graph of a straight line that touches the x-axis at 1 and extends infinitely up and down.
the graph of cos(x)=1 when x=0the graph of sin(x)=0 when x=0.But that only tells part of the story. The two graphs are out of sync by pi/2 radians (or 90°; also referred to as 1/4 wavelength or 1/4 cycle). One cycle is 2*pi radians (the distance for the graph to get back where it started and repeat itself.The cosine graph is 'ahead' (leads) of the sine graph by 1/4 cycle. Or you can say that the sine graph lags the cosine graph by 1/4 cycle.
Easy. Same thing as the graph of f(x) = x^2 + 1 which have NO intercept.
6
Step 1. Determine what will be on the graph. Step 2. Make the graph.
x -3y = 0 -x = -x -3y=-x /-3 = /-3 y=1/3x Then solve y for different values of x, record the data , then graph the x and y position for each value of x. so for if x =1 y = 1/3 so one point on the graph is (1,1/3)