d/dx(e^2x) = 2xe^2x
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By using: ∫uv = u∫v - ∫u'∫v twice. ∫x2exdx let u = x2, v = ex, then: ∫x2exdx = x2∫exdx - ∫d/dx(x2)∫exdx dx = x2ex - ∫2xexdx Again, let u = 2x, v = ex, then: = x2ex - (2x∫exdx - ∫d/dx(2x)∫exdx dx) = x2ex - 2xex +∫2exdx = x2ex - 2xex + 2ex + C
ex+f = c -dx ex+dx = c -f x(e+d) = c -f x = c -f/(e+d)
d/dx e3x = 3e3x
e is a number equalling approximately 2.71828 It is special because it's derivative is the same as it [ie. d/dx (ex) = ex].
The natural logarithm of a variable x, is a variable y, such that ey = x. The constant e, is about 2.718281828, or more formally, e is a number such that the deriviative d/dx of ex = x.