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Solve 4x plus 3y equals 8x plus y for y?
4x + 3y = 8x + y so 3y - y = 8x - 4x ie 2y = 4x so y = 2x
Solve by substition 4x plus 3y equals 1 y equals 2x plus 8?
4x + 3y = 1y = 2x + 8 Take the first part: 4x + 3y = 1y 4x = 1y - 3y 4x = -2y x = -y/2 Substitute x in second part: 1y = 2x + 8 1y = -2y/2 + 8 1y = -1y + 8 2y = 8 y = 4 Substitute y into either part: 1y = 2x + 8 1(4) = 2x + 8 4 - 8 = 2x -4 = 2x x = -2 Therefore: x = -2 y = 4
10x-5y plus 2x-3y?
10x - 5y + 2x - 3y = 12x - 8y
5y - 2y equals 3y plus 2 what is the answer?
5y-2y= 3y+2 5y-2y-3y= 2 0y= 2
What is the solution to the system of equations 3x plus 2y equals 13 and 2x plus 3y equals 12?
2x+3y=12 ......1st equation 3x+2y=13 .......2nd equation ____________________________________ multiplying 1stt equation by 3 and 2nd equation by 2 3x(2x+3y=12) 2x(3x+2y=13) _______________________________ now the equations become 6x+9y=36 ...3rd 6x+4y=26 ....4th by solving both equation(substractinf 4th from 3rd) we get.. 5y=10 therefore y=2 and x=3
How do you solve this equation and check you answer 2x-3y equals 8 x-2y equals 2?
x=10 y=4
How do you solve y-2y'-3y equals 0?
For y - 2y - 3y equals 0, y equals 0.
Solve by the method of elimination 2x plus 3y equals 40 3x plus 2y equals 20?
y=16 x= -4
How would you solve 6xn plus 7y equals -6 -2x-3y equals 2 using addition method?
6x+7y=-6 3(-2x-3y=2) +________ -2y=0 => y=0 Therefore x=-1
How do you do this 2x-3y equals 4?
2x - 3y = 4This can't be solved, although you can express each variable in terms of the other.x = (4-3y)/2y = (2x-4)/3
Solve 4x plus 3y equals 8x plus y for y?
4x + 3y = 8x + y so 3y - y = 8x - 4x ie 2y = 4x so y = 2x
5x-2y plus 3z-2x-y-4z equals?
5x-2y+3z-2x-y-4z=3x-3y-z
What is the locus of points that satisfies both equations 2x-3y equals 5 and x-2y equals 1?
2x-3y=5 and x-2y=12x-3y+2y=5 and x-2y+2y=12x-y=5 and x=12(1)-y=52-y=52-y-2=5-2-y=3y=-3(x,y) is (1,-3)
Solve for x 2x plus 2y equals 8 3x plus 3y equals 6?
Multiply first equation by 1.5, giving 3x + 3y = 12, but we are told that 3x + 3y = 6. If there isn't an error in the question then 2 = 1!
When x equals 5 and y equals 3 by how much does the value of 3x plus 2y exceed the value of 2x plus 3y?
2. If x=5 & y =3 then: 3x + 2y = 3 x 5 + 2 x 3 = 15 + 6 = 21 2x + 3y = 2 x 5 + 3 x 3 = 10 + 9 = 19 ⇒ 3x+2y exceeds 2x+3y by 21 - 19 = 2. Alternatively: 3x+2y exceeds 2x+3y by: (3x+2y) - (2x + 3y) = 3x + 2y - 2x - 3y = x - y If x=5 & y=3 then this becomes: x - y = 5 - 3 = 2
3x plus 2y equals -3 2x plus 3y equals -2?
(-1, 0)
How do you do the elimination method of 2X plus 3Y equals 1?
Usually elimination is used on two equations and is called linear combination. You could solve for "y." That is customary. 2x+3y=1 3y=-2y+1 y=(-2/3)x+1/3
