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How do you solve this equation and check you answer 2x-3y equals 8 x-2y equals 2?

x=10 y=4


How do you solve y-2y'-3y equals 0?

For y - 2y - 3y equals 0, y equals 0.


Solve by the method of elimination 2x plus 3y equals 40 3x plus 2y equals 20?

y=16 x= -4


How Do you Solve 2x-3y equals 2 3x plus 2y equals 3?

Given: 2x - 3y = 2 3x + 2y = 3 Take the first equation, and solve for x: x = (2 + 3y) / 2 Now plug it into the second equation: ∴ 3(2 + 3y) / 2 + 2y = 3 ∴ 3 + 9y/2 + 2y = 3 ∴ 9y/2 + 2y = 0 ∴ 22y = 0 ∴ y = 0 Then you can take that value of y, and plug it into either of our first equations to find x; 2x - 3y = 2 ∴ 2x - 3(0) = 2 ∴ 2x = 2 ∴ x = 1 So x is equal to one, and y is equal to zero.


How would you solve 6xn plus 7y equals -6 -2x-3y equals 2 using addition method?

6x+7y=-6 3(-2x-3y=2) +________ -2y=0 => y=0 Therefore x=-1


How do you do this 2x-3y equals 4?

2x - 3y = 4This can't be solved, although you can express each variable in terms of the other.x = (4-3y)/2y = (2x-4)/3


Solve 4x plus 3y equals 8x plus y for y?

4x + 3y = 8x + y so 3y - y = 8x - 4x ie 2y = 4x so y = 2x


5x-2y plus 3z-2x-y-4z equals?

5x-2y+3z-2x-y-4z=3x-3y-z


What does 3y equals 12 equals what does 2y equal?

If 3y = 12, 2y = 8


3x plus 2y equals -3 2x plus 3y equals -2?

(-1, 0)


What is the locus of points that satisfies both equations 2x-3y equals 5 and x-2y equals 1?

2x-3y=5 and x-2y=12x-3y+2y=5 and x-2y+2y=12x-y=5 and x=12(1)-y=52-y=52-y-2=5-2-y=3y=-3(x,y) is (1,-3)


Solve for x 2x plus 2y equals 8 3x plus 3y equals 6?

Multiply first equation by 1.5, giving 3x + 3y = 12, but we are told that 3x + 3y = 6. If there isn't an error in the question then 2 = 1!