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What is sin of 3 pi over 2?
Sin(3pi/2) = Sin(2pi - pi/2) Double angle Trig. Identity. Hence Sin(2pi)Cos(pi/2) - Cos(2pi) Sin(pi/2) Sin(2pi) = 0 Cos(pi/2) = 0 Cos(2pi) = 1 Sin(pi/2) = 1 Substituting 0 x 0 - 1 x 1 = 0 - 1 = -1 The answer!!!!!
How can I solve tan of 3 theta -sqrt of 3 equals 0 for theta?
tan3A-sqrt3=0 tan3A=sqrt3 3A=tan^-1(sqrt3) 3A= pi/3+npi A=pi/9+npi/3 n=any integer
How do you solve x2 81 equals 0?
x: x2 - 81 = 0
How do you solve 27.82 equals X squared divided by Sin squared x?
Here is a way to solve 27.82 = X2/SIN2(X) using successive approximations or bracketing: First, take the square root of each side: 5.27 = X/SIN(X) SIN(X) has values from 0 to 1 in the first quadrant (0 to 90 deg.) and from 1 to 0 in the second quadrant (90 to 180 deg.) as seen in a table of trig functions. To bracket the answer, plug in values for X in radians; 90 deg. = Pi/2 radians where Pi =3.1415. Pi/2 radians = 1.571 For values of X from 0 to Pi/2, the value of X is too small, so X > 1.571. Since SIN(X) is negative for angles of 180 to 360 deg., the answer should lie between X = 1.571 and X = 3.1415 (Pi radians or 180 deg.) Next, try an answer that lies halfway between 1.571 and 3.1415: Let X = (1.571+3.1415)/2 = 2.356 and solve for X/SIN(X) = 3.33 Since this answer is too small, X must lie between 2.356 and 3.1415 If we continue to bracket the value of X, after a few more steps, we find that if X = 2.621, X/SIN(X) = 5.269 which rounds up to 5.27 This problem can be more easily solved by setting it up in an Excel spread sheet and simply plugging in values for X to converge on the answer.
What is the lim of h if it equals 0 Sinxcosh plus cosxsinh minus sinx divided by h?
lim(h→0) (sin x cos h + cos x sin h - sin x)/h As h tends to 0, both the numerator and the denominator have limit zero. Thus, the quotient is indeterminate at 0 and of the form 0/0. Therefore, we apply l'Hopital's Rule and the limit equals: lim(h→0) (sin x cos h + cos x sin h - sin x)/h = lim(h→0) (sin x cos h + cos x sin h - sin x)'/h' = lim(h→0) [[(cos x)(cos h) + (sin x)(-sin h)] + [(-sin x)(sin h) + (cos x)(cos h)] - cos x]]/0 = cosx/0 = ∞
