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To solve a system of equations like 3x-2y=-7, you typically need another equation to find a unique solution. If there is only one equation given, the system is underdetermined and has infinite solutions. However, if you have additional information or constraints, you can potentially narrow down the possible solutions. In this case, without another equation or constraint, the system is unsolvable as it is currently presented.
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JordanFirst of all there is only an expression, there is no equation. Limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc.
Second, in order to solve a system with two unknown variables, you need two equations, not just one.
First of all there is only an expression, there is no equation. Limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc.
Second, in order to solve a system with two unknown variables, you need two equations, not just one.
First of all there is only an expression, there is no equation. Limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc.
Second, in order to solve a system with two unknown variables, you need two equations, not just one.
First of all there is only an expression, there is no equation. Limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc.
Second, in order to solve a system with two unknown variables, you need two equations, not just one.
First of all there is only an expression, there is no equation. Limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc.
Second, in order to solve a system with two unknown variables, you need two equations, not just one.
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How do you solve linear equations by using elimination?
You multiply one or both equations by some constant (especially chosen for the next step), and add the two resulting equations together. Here is an example: (1) 5x + 2y = 7 (2) 2x + y = 3 Multiply equation (2) by -2; this factor was chosen to eliminate "y" from the resulting equations: (1) 5x + 2y = 7 (2) -2x -2y = -6 Add the two equations together: 3x = 1 Solve this for "x", then replace the result in any of the two original equations to solve for "y".
How would you know if a linear system has a solution?
One way is to look at the graphs of these equations. If they intersect, the point of intersection (x, y) is the only solution of the system. In this case we say that the system is consistent. If their graphs do not intersect, then the system has no solution. In this case we say that the system is inconsistent. If the graph of the equations is the same line, the system has infinitely simultaneous solutions. We can use several methods in order to solve the system algebraically. In the case where the equations of the system are dependent (the coefficients of the same variable are multiple of each other), the system has infinite number of solutions solution. For example, 2x + 3y = 6 4y + 6y = 12 These equations are dependent. Since they represent the same line, all points that satisfy either of the equations are solutions of the system. Try to solve this system of equations, 2x + 3y = 6 4x + 6y = 7 If you use addition or subtraction method, and you obtain a peculiar result such that 0 = 5, actually you have shown that the system has no solution (there is no point that satisfying both equations). When you use the substitution method and you obtain a result such that 5 = 5, this result indicates no solution for the system.
What is the answer for -4x 4y-8 and x-4y-7 using matrices?
Oh, dude, using matrices for these two equations, you'd set up a system like this: [-4 4 -8] [x] = [0] and [1 -4 -7] [y] = [0]. Solve it however you want, like with Gaussian elimination or something, and you'll find the values of x and y that make both equations true. So, like, have fun crunching those numbers, I guess.
What is called Substitution method?
When you have a system of equations and you can solve for one in terms of th others and then replace it in the other equations that is substitution. x+y=15 x-y=1 well the second one can be x=1+y x+y=15 then can be (1+y)+y=15 by substitution. 1+2y=15 2y=14 y=7 Then x+7=15 x=8
Is (-1 1) a solution to this system of equations y 3x 4 4y - 3 x -7?
Without any equality signs the given terms can't be considered to be equations
