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Equations have solutions. I'll assume that's x^2 - 4x + 41 = 0 since this website can't reproduce plus or equals signs in questions. That doesn't factor neatly. Using the quadratic formula, we find two imaginary solutions: 2 plus or minus i times the square root of 37
x = 8.082762530298219i
x = -4.082762530298219i
where i is the imaginary square root of -1
no its is x^2-4x=41
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What is 4x-x2?
4x-x2 = 2
What is X2 divided by -4x?
6
How do you solve y-4x 1?
How do you solve y=-4x+1
How do you factorise x2 plus 4x?
X2 + 4xx(x + 4)=======
Find three consecutive odd numbers such that the sum of their squares is a four-digit with all four digits the same?
the three numbers are: x - 2, x, x+2 the sum of their squares: (x-2)2+ x2 + (x+2)2 = x2 - 4x + 4 + x2 + x2 + 4x + 4 = 3x2 + 8 = n*1111 n= 1,2,3 ... 9 x= sqrt((n*1111 - 8)/3) n = 5, so x = 43 or -43 and the numbers are: -45, -43, -41 or 41, 43, 45
Solve x2 - 4x - 9 equals 0 by completing the square?
x2 - 4x - 9 = 0 ∴ x2 - 4x = 9 ∴ x2 - 4x + 4 = 13 ∴ (x - 2)2 = 13 ∴ x - 2 = ±√13 ∴ x = 2 ± √13
How do you solve the equation Factorise x3 4x?
X(X2 - X)
Solve 4x equals 72?
4x = 72.divide both sides by 4x = 18
How do you solve x2 plus 4x equals 1?
x2 + 4x = 1 x2 + 4x - 1 = 0 in the quadratic formula (b2+- Sqr(4ac))/2a, a = 1 b = 4 c = -1 so x = 8 +- i
How do you solve for the problem x squared minus 10 equals 4x plus 11?
x2-10 = 4x+11 x2-4x-10-11 = 0 x2-4x-21 = 0 (x+3)(x-7) = 0 x = -3 and x = 7
Solve x2 plus 4x plus 3 equals 0?
x2 + 4x + 3 = 0 (x + 1)(x + 3) = 0 x ∈ {-3, -1}
What is 4x-x2?
4x-x2 = 2
X2 - 4x - 29 equals -10?
Assuming that by expressing that equation as a question you're looking to solve for x: x2 - 4x - 29 = -10 x2 - 4x + 4 = 23 (x - 2)2 = 23 x - 2 = ± √23 x = 2 ± √23
Solve by factoring x2 10x -16?
Given: x2 + 10x - 16 Let: x2 + 10x - 16 = 0 x2 + 10x - 16 = 0 ∴ x2 + 10x + 25 = 16 + 25 ∴ (x + 5)2 = 41 ∴ x = -5 ± √41 ∴ x2 + 10x - 16 = (x + 5 + √41)(x + 5 - √41)
What is the y-coordinate of y equals x2 - 4x plus 12?
It can be anything from 41/4 to infinite.
X2 plus 4x-6 equals 0?
Assuming that by writing that equation as a question, you mean to ask how to solve it for x, that can be done as follows: x2 + 4x - 6 = 0 x2 + 4x + 4 = 10 (x + 2)2 = 10 x + 2 = √20 x = -2 ± √20
How do you solve the limit as x approaches zero of 1 over x minus 4 plus 1 over x plus 4 all over x?
Limx→0 [ 1 / (x - 4) + 1 / (x + 4) ] / x = Limx→0 1 / (x2 - 4x) + 1 / (x2 + 4x) = Limx→0 (x2 + 4x) / (x4 - 16x2) + (x2 - 4x) / (x4 - 16x2) = Limx→0 (x2 + 4x - 4x + x2) / (x4 - 16x2) = Limx→0 2x2 / (x4 - 16x2) = Limx→0 2 / (x2 - 16) = 2 / (0 - 16) = -1/8
