Let's explain with an example: 2x - 7y = 11 5x + 7y = 3 To solve this system of equations by elimination we "add" the second equation to the first equation. So basically: 2x + 5x - 7y + 7y = 11 + 3 Which then symplifies to: 7x = 14 and x = 2 Then plug x = 2 into the original equation: 5(2) + 7y = 3 Which leads to: y = -1 So the solution is (2,-1).
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Given: 2y = x + 2 x - 3y = -5 ∴ y = x/2 + 1 ∴ x - 3(x/2 + 1) = -5 ∴ x - 3x/2 - 1 = - 5 ∴ -x/2 = -4 ∴ x = 2 ∴ 2y = 2 + 2 ∴ y = 2 ∴ {x, y} = {2, 2}
9x-6y-(12*2y)=0 9x-6y-24y=0 9x-30y=o 9x=30y 3x=10y y=0.3x x=10/3y
4x-2y = 6 -7x+2y = -15 Add both equations together in order to eliminate y: -3x = -9 Divide both sides by -3 in order to find the value of x: x = 3 Substitute the value of x into the original equations to find the value of y: Solution: x = 3 and y = 3
Use the substitution method to solve the system of equations. Enter your answer as an ordered pair.y = 2x + 5 x = 1
You solve this by theoretically diverting the hypotenuse of the x divided by the overall beneficial procedure of y