you make an equation of the line:
standard form: (y-y1)= m(x-x1)
so if the point is (2, -2) and you want to make it perpendicular to the line with a slope (m) of 1/2, the perpendicular slope is the negative recipricle which is -2
so the equation would be: (y--2)= -2(x-2)
(y+2)= -2(x-2)
y+2= -2x +4
-2 -2
Slope Intercept Form: y= -2x +2
That depends on the equation that it is perpendicular too which has not been given but both equations will meet each other at right angles.
That would depend on its slope which has not been given.
Equilateral triangles
Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4
You solve this type of problem using the following steps. 1) Write your original equation in slope-intercept form, that is, solved for "y". (The line is already in that form in this case). You can read off the slope directly: in an equation of the form: y = mx + b m is the slope. 2) Calculate the slope of the perpendicular line. Since the product of the slopes of perpendicular lines is -1, you can divide -1 by the slope you got in part (1). 3) Use the generic equation y - y1 = m(x - x1), for a line that has a given slope "m" and passes through point (x1, y1). Replace the given coordinates (variables x1 and y1). Simplify the resulting equation, if required.
That depends on the equation that it is perpendicular too which has not been given but both equations will meet each other at right angles.
Yes, I could, if I knew the slope of the line given.
That would depend on its slope which has not been given.
Equilateral triangles
equilateral triangles
A perpendicular to the line which passes through the given point.
The standard equation for a straight line is y = mx + c. Let this be the equation of the original line. Note that m and c are known values. Let the given point coordinates be (a,b)Two straight lines are perpendicular if the product of their gradients (slopes) is -1.The slope (m1) of the perpendicular line is therefore m1 = -1/mWhen y = b then x = a so the equation for the perpendicular line is y = m1x + d, and substituting gives : b = -a/m + d and this will enable d to be calculated.NOTE : In the absence of information for the equation of the original line and the coordinates of the given point then this is a general rather than a specific answer.
The shortest path is a line perpendicular to the given line that passes through the given point.
Given a straight line joining the points A and B, the perpendicular bisector is a straight line that passes through the mid-point of AB and is perpendicular to AB.
Coordinate geometry
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4