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you make an equation of the line:

standard form: (y-y1)= m(x-x1)

so if the point is (2, -2) and you want to make it perpendicular to the line with a slope (m) of 1/2, the perpendicular slope is the negative recipricle which is -2

so the equation would be: (y--2)= -2(x-2)

(y+2)= -2(x-2)

y+2= -2x +4

-2 -2

Slope Intercept Form: y= -2x +2

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Q: How do you write an equation that is perpendicular to a given line and passes through the given point?
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