The standard equation for a straight line is y = mx + c. Let this be the equation of the original line. Note that m and c are known values. Let the given point coordinates be (a,b)
Two straight lines are perpendicular if the product of their gradients (slopes) is -1.
The slope (m1) of the perpendicular line is therefore m1 = -1/m
When y = b then x = a so the equation for the perpendicular line is y = m1x + d, and substituting gives : b = -a/m + d and this will enable d to be calculated.
NOTE : In the absence of information for the equation of the original line and the coordinates of the given point then this is a general rather than a specific answer.
A line that is perpendicular to the segment of a plane and passes through the midpoint.
Slope: -2 Equation: y--1 = -2(x-3) => y = -2x+5
which equation has a slope of -1/2 and a graph that passes through (-3,4)?
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
Given a straight line joining the points A and B, the perpendicular bisector is a straight line that passes through the mid-point of AB and is perpendicular to AB.
If you mean 7 = 7x-3 then the perpendicular slope is -1/7 and the equation is y = -1/7x
That depends on the equation that it is perpendicular too which has not been given but both equations will meet each other at right angles.
Perpendicular slope: -1/4 Perpendicular equation: y-0 = -1/4(x-3) => y = -0.25x+3
2-3
General formula
Without an equality sign and not knowing the plus or minus values of y and 7 it can't be considered to be a straight line equation therefore finding its perpendicular equation is impossible.
That would depend on its slope which has not been given.
Perpendicular slope: 1/2 Perpnedicular equation: y-5 = 1/2(x-2) => y = 0.5x+4
If you mean y = 3x+8 then the perpendicular slope will be -1/3 and the equation works out as 3y = -x+9
Perpendicular slope: -2/5 Perpendicular equation: y--4 = -2/5(x-3) => 5y--20 = -2x-3 => 5y = -2x-14 Perpendicular equation in its general form: 2x+5y+14 = 0
A line that is perpendicular to the segment of a plane and passes through the midpoint.
As for example the perpendicular equation to line y = 2x+6 could be y = -1/2x+6 because the negative reciprocal of 2x is -1/2x