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The standard equation for a straight line is y = mx + c. Let this be the equation of the original line. Note that m and c are known values. Let the given point coordinates be (a,b)

Two straight lines are perpendicular if the product of their gradients (slopes) is -1.

The slope (m1) of the perpendicular line is therefore m1 = -1/m

When y = b then x = a so the equation for the perpendicular line is y = m1x + d, and substituting gives : b = -a/m + d and this will enable d to be calculated.

NOTE : In the absence of information for the equation of the original line and the coordinates of the given point then this is a general rather than a specific answer.

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Elysia Terry

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3y ago
  1. A line passes through (3, 5) and (6, 14) What is the equation of the line in point -slope form?
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Q: How do I write the equation of the line that passes through the given point and is perpendicular to the given line Write the answer in slope-intercept form?
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