I am 11 and I tried this for fun.
I found 287 combinations.
Now I am working on 9 digit with numbers 1 - 9.
Wish me luck...
There are 5,040 combinations.
To calculate the number of 4-digit combinations you can get from the numbers 1, 2, 2, and 6, we need to consider that the number 2 is repeated. Therefore, the total number of combinations is calculated using the formula for permutations of a multiset, which is 4! / (2!1!1!) = 12. So, there are 12 unique 4-digit combinations that can be formed from the numbers 1, 2, 2, and 6.
I can't
First digit can be one of four, second can be one of the remaining three etc so 4 x 3 x 2 x 1 = 24 combinations. This is known as factorial 4 (or 4 factorial) and is symbolised as "4!".
18
There are 840 4-digit combinations without repeating any digit in the combinations.
There are 210 4 digit combinations and 5040 different 4 digit codes.
216
There are 5,040 combinations.
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
There would be 9*9*9*9 or 6561 combinations.
1296 or (6^4)
4+4+4+4+4= 20
This question needs clarificatioh. There are 4 one digit number combinations, 16 two digit combinations, ... 4 raised to the n power for n digit combinations.
5
10,000
"There are 10,000 different combinations"-Hey nick! love dave and jalp