5040
The number of 7 letter permutations of the word ALGEBRA is the same as the number of permutation of 7 things taken 7 at a time, which is 5040. However, since the letter A is duplicated once, you have to divide by 2 in order to find out the number of distinct permutations, which is 2520.
There are 8! = 40320 permutations.
4! 4 * 3 * 2 * 1 = 24
There are 6! = 720 permutations.
The number of permutations of the letters MASS where S needs to be the first letter is the same as the number of permutations of the letters MAS, which is 3 factorial, or 6. SMAS SMSA SAMS SASM SSMA SSAM
There are 5*4*3 = 60 permutations.
The word "DECAGON" has 7 letters, with the letter "A" appearing once, "C" appearing once, "D" appearing once, "E" appearing once, "G" appearing once, "N" appearing once, and "O" appearing once. To find the number of different 4-letter permutations, we need to consider combinations of these letters. Since all letters are unique, the number of 4-letter permutations is calculated using the formula for permutations of n distinct objects taken r at a time: ( P(n, r) = \frac{n!}{(n-r)!} ). Here, ( n = 7 ) and ( r = 4 ), so the number of permutations is ( P(7, 4) = \frac{7!}{(7-4)!} = \frac{7!}{3!} = 7 \times 6 \times 5 \times 4 = 840 ). Thus, there are 840 different 4-letter permutations that can be formed from the letters in "DECAGON."
There are 195 3-letter permutations.
How many four-letter permutations can be formed from the letters in the word DECAGON?
420.
There are 8P5 = 8*7*6*5*4 = 6720
There are three that I can see, there's clip, board and lip.
120 triangles.
There are 7893600 permutations.
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There are 9 * 8 * 7, or 504, three letter permutations that can be made from the letters in the work CLIPBOARD.
There are 8