There are 5,040 combinations.
You can make six different combinations: 123 132 213 231 321 312. If you just need to know the number of combinations, you could find the answer without writing everything out by letting x represent the number of digits and calculating x*(x-1).
There are: 12345C3 = 3.134847985*1011
Just one. * * * * * Depends on how many numbers are on each ring. If there are x numbers, then the total number of combinations (actually they are permutations) is x*x*x or x3.
Assuming there are 5 check boxes and the respondent may check any number of them, the answer is 25 = 32 combinations.
There are infinitely many numbers and so infinitely many possible combinations.
There are 120 permutations and 5 combinations.
9000
Assuming you are using the standard English alphabet, the number of combinations you can make are: 26 x 26 = 676 combinations.
13579
36324
There are only 10 combinations. In each combination one of the 10 digits is left out.
654321-100000= 554321 combinations
The answer is 31C5 = 31!/[26!5!] = 169,911
10,000 combinations.
There are twelve possible solutions using the rule you stated.
266 x 10 = 3089157760.