Assuming the order of the colors doesn't matter, that would be 6 over 3 (written as a 6 over a 3, without a fractional line in between, within parentheses). That's the same as (6 x 5 x 4) / (1 x 2 x 3).
Two . . . . . 38 and 83.
There are 32C3 = 32*31*30/(3*2*1) = 4960 combinations. I do not have the inclination to list them all.
There are: 12345C3 = 3.134847985*1011
It can have 120 combinations . . .
If the question concerned the number of combinations of three different coins, the answer is 23-1 = 7. If the coins are a,b,and c, the combinations are a, b, c, ab, ac, bc, abc. If two of the coins are the same there are only 5 combinations and if all three are the same there are 3.
8
24
There are 3 primary colors; Red, Yellow and green. Mixing combinations of these colors will give you all the colors.
3*5*8 = 120
You could make 10*10*10*26*26*26 combinations, or 17576000 combinations.
You can get all colors with varying combinations of the 3.
11*3*3 = 99 combinations.
13 combinations of 3
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
72 possible combinations.3 x 3 = 9 cells; 2 colors eachFORMULA: n * (n-1) = 9*8 = 72
9.
36