0
There are
1 combination of 4 colours out of 4,
4 combinations of 3 colours out of 4, 6 combinations of 2 colours out of 4,
4 combinations of 1 colour out of 4.
A grand total of 15 (= 24-1) combinations.
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ā 11y ago
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How many combinations of 5 numbers are there for 1-30?
The number of combinations of r numbers out of n is nCr = n!/[r!*(n-r)!] where n! = 1*2*3...*n So here n = 30, r = 5 which gives 30*29*28*27*26/(5*4*3*2*1) = 142,506
How do you do combinations in math?
nCr=n!/r!/(n-r)!
How many ways can 5 sopranos and 4 altos be selected from 7 sopranos and 9 altos?
First, let us consider each case separately.Looking at the first case, we need to find how many ways we can choose 5 sopranos from 7 sopranos. When we need to find the amount of combinations of n objects when we can only choose r objects, we can use the formula:combinations = n!/r!(n-r)!The ! symbol means to multiply that number by all the numbers before it.So 4! = 4 * 3 * 2 * 1 = 24n = the total number of sopranos we can choose from (7 sopranos)r = the amount of sopranos we can actually choose (5 sopranos)So plugging everything into the formula:combinations = 7!/5!(7-5)! = 7!/5!*2! = (7*6*5*4*3*2)/(5*4*3*2)*(2) = 21 different combinations.Next, let's consider the altos.Our formula (combinations = n!/r!(n-r)!) is the same so we just need to plug in a different set of values.n = the total number of altos we can choose from (9 altos)r = the amount of altos we can actually choose (4 altos)So, using the formula:combinations = 9!/4!(9-4)! = 9!/4!*5! = (9*8*7*6*5*4*3*2)/(5*4*3*2)*(4*3*2) = 126 different combinations.If we treat the choosing of the alto's and soprano's as two independent events, then we can figure out the number of combinations of both events by multiplying the number of combinations for both. In this case, we would multiply the number of combinations for choosing 5 from 7 sopranos (21) by the number of combinations for choosing 4 from 9 altos (126.) This gives us 21 * 126 = 2646 different combinations.
How can you figure out combinations in math?
If you have N things and want to find the number of combinations of R things at a time then the formula is [(Factorial N)] / [(Factorial R) x (Factorial {N-R})]
How many hundreds in 480?
4 r=80
How many 4 number combinations are their using numbers 0 9?
10,000 * * * * * WRONG! That is the number of permutations, NOT the number of combinations. The number of combinations denoted by nCr = n!/[r!*(n-r)!] = 10!/[4!*6!] = 10*9*8*7/(4*3*2*1) = 210
How can you Find the number of combinations of objects in a set?
The number of R-combinations in a set of N objects is C= N!/R!(N-R)! or the factorial of N divided by the factorial of R and the Factorial of N minus R. For example, the number of 3 combinations from a set of 4 objects is 4!/3!(4-3)! = 24/6x1= 4.
How many possible different combinations of numbers r possible in just the last 4 numbers?
10,000
How many combinations of 6 numbers are there in 44 numbers?
Just use combinations formula. nCr, where n=44, r=6. Plug it into the calculator or use the formula, nCr = n!/[r!(n-r)!] And you should get 7059052 as the number of combinations.
How do you evaluate combinations?
If you have n objects and you are choosing r of them, then there are nCr combinations. This is equal to n!/( r! * (n-r)! ).
How many combinations of 5 numbers are there for 1-30?
The number of combinations of r numbers out of n is nCr = n!/[r!*(n-r)!] where n! = 1*2*3...*n So here n = 30, r = 5 which gives 30*29*28*27*26/(5*4*3*2*1) = 142,506
How many combinations can be made using of fifteen thing taken four at a time?
Formula: nCr = n! divided by (n-r)! x r!where n is the number of things to choose from and you choose r of them15C4 = 15!divided by (15-4)! x 4! = 1365 ways
How many 8 numbers combinations can you make from the numbers 1 to 49?
nCr = n!/((n-r)!r!) → 49C8 = 49!/((49-8)!8!) = 49!/(41!8!) = 450,978,066 combinations.
How many number combinations can you make using the numbers 9, 3, 1, and 7?
To determine the number of combinations possible using the numbers 9, 3, 1, and 7, we can use the concept of permutations. A permutation is an arrangement of objects in a specific order. In this case, we want to find the number of permutations of all the numbers. The formula for permutations of n objects taken r at a time is given by: P(n, r) = n! / (n - r)! Where "!" denotes the factorial function. In this case, we have 4 numbers and we want to arrange all of them, so r = 4. P(4, 4) = 4! / (4 - 4)! = 4! / 0! = 4! / 1 = 4 * 3 * 2 * 1 = 24 Hence, there are 24 different number combinations that can be made using the numbers 9, 3, 1, and 7.
How do you do combinations in math?
nCr=n!/r!/(n-r)!
Find the number of combinations of 10 things taken 6 at a time?
Try 151,600! Permutations & Combinations. P(n,r)=n!(nār)! not P(n,r)=n!/(n!-r!)r! ?
How many 4 different numbers of combination can you get from number1-20?
There are 4845 combinations of 4 numbers from the set 1 - 20 nCr = n!/r!(n-r)! ⇒ 20C4 = 20!/4!(20-4)! = 20 x 19 x 18 x 17/4 x 3 x 2 x 1 = 4845
