0
Add your answer:
Earn +20 pts
How many possible combinations can be made from 10 items?
To calculate the number of possible combinations from 10 items, you can use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, n is the total number of items (10) and r is the number of items you are choosing in each combination (which can range from 1 to 10). So, if you are considering all possible combinations (r=1 to 10), the total number of combinations would be 2^10, which is 1024.
If using numbers 0 through 9 how many different 4 digit combinations can be made?
To calculate the number of different 4-digit combinations that can be made using numbers 0 through 9, we use the concept of permutations. Since repetition is allowed, we use the formula for permutations with repetition, which is n^r, where n is the number of options for each digit (10 in this case) and r is the number of digits (4 in this case). Therefore, the number of different 4-digit combinations that can be made using numbers 0 through 9 is 10^4, which equals 10,000 combinations.
How many combinations of 5 numbers are there for 1-30?
To calculate the number of combinations of 5 numbers chosen from 1 to 30, we use the combination formula which is nCr = n! / (r!(n-r)!). In this case, n = 30 and r = 5. Plugging these values into the formula, we get 30! / (5!(30-5)!) = 142,506 total combinations.
How many combinations of 4 numbers in 45 numbers?
To calculate the number of combinations of 4 numbers out of 45, we use the combination formula, which is nCr = n! / (r!(n-r)!). In this case, n = 45 (total numbers) and r = 4 (numbers chosen). Plugging these values into the formula, we get 45C4 = 45! / (4!(45-4)!) = 45! / (4!41!) = (45 x 44 x 43 x 42) / (4 x 3 x 2 x 1) = 1,086,132. Therefore, there are 1,086,132 possible combinations of 4 numbers chosen from 45.
How do you do combinations in math?
nCr=n!/r!/(n-r)!
How many 4 number combinations are their using numbers 0 9?
10,000 * * * * * WRONG! That is the number of permutations, NOT the number of combinations. The number of combinations denoted by nCr = n!/[r!*(n-r)!] = 10!/[4!*6!] = 10*9*8*7/(4*3*2*1) = 210
How can you Find the number of combinations of objects in a set?
The number of R-combinations in a set of N objects is C= N!/R!(N-R)! or the factorial of N divided by the factorial of R and the Factorial of N minus R. For example, the number of 3 combinations from a set of 4 objects is 4!/3!(4-3)! = 24/6x1= 4.
How many possible different combinations of numbers r possible in just the last 4 numbers?
10,000
How many 4 number combinations are there with 16 numbers?
To calculate the number of 4-number combinations possible with 16 numbers, you would use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, n = 16 (the total number of numbers) and r = 4 (the number of numbers in each combination). Plugging these values into the formula, you would calculate 16C4 = 16! / 4!(16-4)! = 1820. Therefore, there are 1820 possible 4-number combinations with 16 numbers.
How many 5 number combinations are there for 59 numbers?
Oh, what a lovely question! To find the number of 5-number combinations from 59 numbers, we can use a formula called combinations. It's like mixing colors on your palette! The formula is nCr = n! / r!(n-r)!, where n is the total numbers (59) and r is the number of selections (5). So, for 59 numbers choosing 5 at a time, there are 5,006,386 unique combinations waiting to be discovered! Just imagine all the beautiful possibilities that can come from those combinations.
How many combinations of 5 are there?
There are 120 combinations of 5 items, which can be calculated using the formula nCr = n! / r!(n - r)!.
How many possible combinations can be made from 10 items?
To calculate the number of possible combinations from 10 items, you can use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, n is the total number of items (10) and r is the number of items you are choosing in each combination (which can range from 1 to 10). So, if you are considering all possible combinations (r=1 to 10), the total number of combinations would be 2^10, which is 1024.
How many combinations of 6 numbers are there in 44 numbers?
Just use combinations formula. nCr, where n=44, r=6. Plug it into the calculator or use the formula, nCr = n!/[r!(n-r)!] And you should get 7059052 as the number of combinations.
How do you evaluate combinations?
If you have n objects and you are choosing r of them, then there are nCr combinations. This is equal to n!/( r! * (n-r)! ).
If using numbers 0 through 9 how many different 4 digit combinations can be made?
To calculate the number of different 4-digit combinations that can be made using numbers 0 through 9, we use the concept of permutations. Since repetition is allowed, we use the formula for permutations with repetition, which is n^r, where n is the number of options for each digit (10 in this case) and r is the number of digits (4 in this case). Therefore, the number of different 4-digit combinations that can be made using numbers 0 through 9 is 10^4, which equals 10,000 combinations.
How many combinations of 5 numbers are there for 1-30?
To calculate the number of combinations of 5 numbers chosen from 1 to 30, we use the combination formula which is nCr = n! / (r!(n-r)!). In this case, n = 30 and r = 5. Plugging these values into the formula, we get 30! / (5!(30-5)!) = 142,506 total combinations.
How many combinations of 4 numbers in 45 numbers?
To calculate the number of combinations of 4 numbers out of 45, we use the combination formula, which is nCr = n! / (r!(n-r)!). In this case, n = 45 (total numbers) and r = 4 (numbers chosen). Plugging these values into the formula, we get 45C4 = 45! / (4!(45-4)!) = 45! / (4!41!) = (45 x 44 x 43 x 42) / (4 x 3 x 2 x 1) = 1,086,132. Therefore, there are 1,086,132 possible combinations of 4 numbers chosen from 45.
